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# A list of positive integers a, b, c, d, e where a < b

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A list of positive integers a, b, c, d, e where a < b [#permalink]  29 Feb 2004, 19:48
A list of positive integers a, b, c, d, e where a < b < c < d < e . The median is 50, mean is 60. What is the least possible value of e?
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77
total value of 5 numbers is 60*5 = 300
median, c=50. In order to have e as low as possible, we have to put a and b as high as possible; a=48 b=49. Therefore, 300-50-49-48 = 153. Finally, to minize e, we have to make d as equal to e as possible. therefore, d=76 and e=77 (sum: 76+77=153)
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Paul

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Hi Paul,

I love this one and only daring attempt. Very neat solution indeed.

Anand.
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