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A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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20 Mar 2013, 18:13

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A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c B. bm/60c C. bc/60m D. 60b/cm E. b/60cm

guys this is how i got to solve the above problem;i found at the rate at which the machine produces a bottle in the said minutes hence c/m.time eqauls work done over rate;in that case,b/c/60m=60bm/c...following my algorithm,i got option A for an answer yet the problem holds B for an answer.what could possibly go wrong?

The machine puts c caps in m minutes or c caps in m/60 hours. Rate = c/m/60 = 60c/m. To put b caps the machine will take:- Time = Work/Rate T = b/60c/m = bm/60c Answer is B. In your algorithm, by mistake you converted minutes into hours by multiplying minutes with 60, you should have divided minutes by 60.

Re: A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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21 Mar 2013, 04:28

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This post received KUDOS

Expert's post

chiccufrazer1 wrote:

A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c B. bm/60c C. bc/60m D. 60b/cm E. b/60cm

guys this is how i got to solve the above problem;i found at the rate at which the machine produces a bottle in the said minutes hence c/m.time eqauls work done over rate;in that case,b/c/60m=60bm/c...following my algorithm,i got option A for an answer yet the problem holds B for an answer.what could possibly go wrong?

A machine puts c caps on bottles in m minutes --> the rate of the machine is (rate) = (job)/(time) = c/m cap/minute.

The time needed to put caps on b bottles (time) = (job)/(rate) = b/(c/m) minutes = bm/c minutes = bm/(60c) hours.

Re: A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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01 Feb 2014, 09:16

chiccufrazer1 wrote:

A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c B. bm/60c C. bc/60m D. 60b/cm E. b/60cm

guys this is how i got to solve the above problem;i found at the rate at which the machine produces a bottle in the said minutes hence c/m.time eqauls work done over rate;in that case,b/c/60m=60bm/c...following my algorithm,i got option A for an answer yet the problem holds B for an answer.what could possibly go wrong?

A machine puts c caps in m minutes per bottle. How many hours will it take to put caps on b bottles?

Re: A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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29 Mar 2014, 00:48

jlgdr wrote:

chiccufrazer1 wrote:

A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c B. bm/60c C. bc/60m D. 60b/cm E. b/60cm

guys this is how i got to solve the above problem;i found at the rate at which the machine produces a bottle in the said minutes hence c/m.time eqauls work done over rate;in that case,b/c/60m=60bm/c...following my algorithm,i got option A for an answer yet the problem holds B for an answer.what could possibly go wrong?

A machine puts c caps in m minutes per bottle. How many hours will it take to put caps on b bottles?

I think this wording is more clear

Cheers J

Hi there,

IMHO the wording is already clear since 1 cap can be per bottle only it cannot be the case that 3 caps are on 1 bottle.

'C' Caps ---> 'm' minutes

1 Cap/bottle ---> m/c minutes

b bottle ---> mb/c minutes

mb/60 c _________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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25 Jun 2014, 21:24

Either we can fix it with the help of a small formula which is : (M1 * D1 * H1)/ W1 = (M2 * D2 * H2)/ W2 where M , D and H stands for Men, Days and Hours invested for each of the 2 Works respectively.

So here it goes: M1= 1 (as we are not given the value) D1 = m/60 (in hrs) H1 = 1 (as we are not given the value) and W1 = c

and

M2 = 1 (as we are not given the value) D2 = x (in hrs) (to be found out) H2 = 1 (as we are not given the value) and W2 = b (as given)

Re: A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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13 Oct 2015, 01:15

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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A machine puts c caps on bottles in m minutes. How many hour [#permalink]

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04 Nov 2015, 14:48

If machine caps c bottles in m minutes, rate per minute is c/m. Rate per hour will be 60c/m. To cap b bottles, machine will need b/(60c/m)=bm/60c hours.

gmatclubot

A machine puts c caps on bottles in m minutes. How many hour
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