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A man can row 50 km upstream and 72 km downstream in 9

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A man can row 50 km upstream and 72 km downstream in 9 [#permalink] New post 23 Nov 2003, 08:36
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

(1) 3
(2) 8
(3) 4
(4) None of the above


This one is interesting too.
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 [#permalink] New post 23 Nov 2003, 09:38
got 4(3rd option) as the answer!
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 [#permalink] New post 23 Nov 2003, 11:22
have the feeling that it is last option , none of the above :?
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 [#permalink] New post 23 Nov 2003, 12:25
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

Current is 4. That question was a bitch. I can't wait for someone to come along and do it in 1/10 of the work that it took me.

50/(r-c)+72/(r+c)=9
70/(r-c)+90/(r+c)=12

-70/(r-c)-100.8/(r+c)=-12.6
70/(r-c)+ 90/(r+c) =12
-10.8/(r+c)=-.6
108/(r+c)=6
108=6r+6c
r+c=18

50/(r-c)+4=9
50=5(r-c)

r-c=10
r+c=18
2r=28
r=14
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 [#permalink] New post 23 Nov 2003, 12:27
FOR THOSE OF YOU WHO SOLVED IT, HOW LONG DID IT TAKE YOU?

(STUPID CAPS LOCK)
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 [#permalink] New post 24 Nov 2003, 04:49
stoolfi wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

Current is 4. That question was a bitch. I can't wait for someone to come along and do it in 1/10 of the work that it took me.

50/(r-c)+72/(r+c)=9
70/(r-c)+90/(r+c)=12

-70/(r-c)-100.8/(r+c)=-12.6
70/(r-c)+ 90/(r+c) =12
-10.8/(r+c)=-.6
108/(r+c)=6
108=6r+6c
r+c=18

50/(r-c)+4=9
50=5(r-c)

r-c=10
r+c=18
2r=28
r=14



it sure was!

it took me almost a light-year

-jay
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 [#permalink] New post 24 Nov 2003, 07:02
Yep, the answer is rate = 4

stoolfi wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

Current is 4. That question was a bitch. I can't wait for someone to come along and do it in 1/10 of the work that it took me.

50/(r-c)+72/(r+c)=9
70/(r-c)+90/(r+c)=12

-70/(r-c)-100.8/(r+c)=-12.6
70/(r-c)+ 90/(r+c) =12
-10.8/(r+c)=-.6
108/(r+c)=6
108=6r+6c
r+c=18

50/(r-c)+4=9
50=5(r-c)

r-c=10
r+c=18
2r=28
r=14


So I suppose you liked the question, huh stoolfi and jay! :lol:
stoolfi,
You have the right approach. I solved in the similiar manner too.

I think the hardest part about this problem is having two unknowns as denominators. I think this was of the hard difficulty. I'll pass more like this one as I come cross them. Good job.
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 [#permalink] New post 27 Nov 2003, 18:57
A man can row 50 km upstream and 72 km downstream in 9 hours

This statement translate into

Upstream rate = 50/t1
Downstream rate = 72/9-t1

He can also row 70 km upstream and 90 km downstream in 12 hours.

This statement translate into

Upstream rate = 70/t2
Downstream rate = 90/12-t2

so 50/t1 = 70/t2 and 72/(9-t1) = 90/(12-t2)

Solve for t2 = 5

Now Rate of current is = 1/2[Downstream Rate - UPstream Rate]

= 1/2 [90/5 - 70/7] = 4

I got this formula from one Inidan book.It is easy to derive.

Perhaps it is same amount of work but just a different approach.
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Re: Rowing man [#permalink] New post 17 May 2004, 18:02
wonder_gmat wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.


A: 50 72 9
B: 70 90 12
X: 20 18 3 (difference b/w A and B)
Y: 80 72 12 (multiply X's with 4)
Z: 60 54 9 (multiply X's data with 3)
W:10 18 (difference b/w Z and A, or Y and B)


From the table, we can conclude that the time to row 10kms upstream = the time to row 18km downstream.

Let that time be k.

(r+c)k = 18
(r-c)k = 10
r = 14/k, c = 4/k

solve for k,
20/(r-c)+18/(r+c) = 3
k = 1.

Answer = c = 4/k = 4/1 = 4
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Re: [#permalink] New post 03 Sep 2011, 08:02
gmatblast wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours
Now Rate of current is = 1/2[Downstream Rate - UPstream Rate]

= 1/2 [90/5 - 70/7] = 4



Can someone tell me more about this rule?
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Last edited by petrifiedbutstanding on 05 Sep 2011, 03:09, edited 1 time in total.
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Re: Rowing man [#permalink] New post 03 Sep 2011, 20:12
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wonder_gmat wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

(1) 3
(2) 8
(3) 4
(4) None of the above


This one is interesting too.


I got the answer in less than 30 secs without writing down a word. Since you are looking for faster approaches, let me write down my thought:

First thing that came to mind was 50/U + 72/D = 9
where U is the upstream speed, D is the downstream speed and D is obviously greater than U.
Now I thought of splitting 9 hrs into 5 hrs and 4 hrs. Why? There was a 50. 5 hrs was screaming out at me and then the remaining would be 4 hrs and 72 is divisible by 4, I know.
If I say that perhaps the time taken to go upstream was 5 hrs, the upstream speed, U, will be 10 km/hr.
If time taken to go downstream is 4 hrs, the downstream speed will be 72/4 = 18 km/hr
Now I need to check if U is actually 10 and D is actually 18. How?
I put it in the other equation.
70/U + 90/D = 12
70/10 + 90/18 = 12
7 + 5 = 12
These values of U and D satisfy.

So difference of speeds of boat and stream is 10 and sum of the speeds is 18.
This would give us two equations: B - S = 10 and B + S = 18
2B = 28
B = 14
So S = 4

GMAT does not require long calculations. If you find yourself making and solving tedious equations, be rest assured that the numbers will fall into place. The 9 hrs given above will not split into 5.2 and 3.8 hrs. It will split into 5 and 4 or 6 and 3 etc. You can pretty much guess the correct answer in the first go by looking at the numerator. 50 is not divisible by 6 but it is divisible by 5. And mind you, all this can be easily done orally. Try to minimize your use of pen and paper; your speed will automatically increase.
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Re: Rowing man [#permalink] New post 06 Sep 2011, 02:15
VeritasPrepKarishma wrote:
wonder_gmat wrote:
A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.

(1) 3
(2) 8
(3) 4
(4) None of the above


This one is interesting too.


I got the answer in less than 30 secs without writing down a word. Since you are looking for faster approaches, let me write down my thought:

First thing that came to mind was 50/U + 72/D = 9
where U is the upstream speed, D is the downstream speed and D is obviously greater than U.
Now I thought of splitting 9 hrs into 5 hrs and 4 hrs. Why? There was a 50. 5 hrs was screaming out at me and then the remaining would be 4 hrs and 72 is divisible by 4, I know.
If I say that perhaps the time taken to go upstream was 5 hrs, the upstream speed, U, will be 10 km/hr.
If time taken to go downstream is 4 hrs, the downstream speed will be 72/4 = 18 km/hr
Now I need to check if U is actually 10 and D is actually 18. How?
I put it in the other equation.
70/U + 90/D = 12
70/10 + 90/18 = 12
7 + 5 = 12
These values of U and D satisfy.

So difference of speeds of boat and stream is 10 and sum of the speeds is 18.This would give us two equations: B - S = 10 and B + S = 18
2B = 28
B = 14
So S = 4

GMAT does not require long calculations. If you find yourself making and solving tedious equations, be rest assured that the numbers will fall into place. The 9 hrs given above will not split into 5.2 and 3.8 hrs. It will split into 5 and 4 or 6 and 3 etc. You can pretty much guess the correct answer in the first go by looking at the numerator. 50 is not divisible by 6 but it is divisible by 5. And mind you, all this can be easily done orally. Try to minimize your use of pen and paper; your speed will automatically increase.



Can you please explain the blue highlighted text?

thanks
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Re: Rowing man [#permalink] New post 06 Sep 2011, 03:38
bidmanager wrote:

Can you please explain the blue highlighted text?

thanks


We got U = 10 and D = 18 i.e. Upstream speed = 10 and Downstream Speed = 18
What do you mean by Upstream speed? It means the speed of the boat while going upstream i.e. against the flow of water. Upstream speed is given by Speed of Boat - Speed of stream i.e. the boat loses some speed because it is going against the stream of water. U = B - S

What do you mean by downstream speed? It means the speed of the boat while going downstream i.e. with the flow of the water. Downstream speed is given by Speed of Boat + Speed of stream i.e. the overall speed of the boat increases because the stream is flowing in the same direction and adds to the speed of the boat. D = B + S
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Re: Rowing man   [#permalink] 06 Sep 2011, 03:38
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