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A man sold 20 articles for $60 and gained 20%. How many

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A man sold 20 articles for $60 and gained 20%. How many [#permalink] New post 28 Jul 2010, 08:20
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A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $90 to incur a loss 20%?

A. 45
B. 36
C. 40
D. 50
E. 48
[Reveal] Spoiler: OA

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Re: Another percent problem [#permalink] New post 28 Jul 2010, 08:35
Production cost per article: $60*(100%-20%) / 20 = $2.40

Required production costs for a loss of 20%: $90*(100% + 20%) = $108

Number of articles to be sold for $108 to incur a 20% loss: $108 / $2.40 = 45

Thus, solution A is correct.
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Re: Another percent problem [#permalink] New post 28 Jul 2010, 15:55
rxs0005 wrote:
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $90 to incur a loss 20%?


A. 45


B. 36


C. 40

D. 50

E. 48


If he sells 20 articles for $60 then selling price for each article is $3. Since he gained 20% ,If the production cost per article is x then x*1.2=3 ==> x=$2.5
If a selling price of $90 for y articles makes a 20% loss then production price for those y articles is 90/.08 = 112.5
Since each article costs 2.5, y*2.5 =112.5 ==> y=45
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Re: Another percent problem [#permalink] New post 28 Jul 2010, 19:25
Please help me here... I get the answer 50. OA is definately correct or am i making some mistake please correct me where i am wrong.

20 articles for $60 means selling price = 3
20% profit is made so Cost Price = 2.5

Man has to incur a loss of 20% means he has to make a total loss of 20% and he sells X units in 90$

60+90 = 0.8 * (C.P. for 20+X units)
C.P. for 20+X units = 75*5/2

But the cost price for one unit is 2.5 so, 75*5/(2*2.5) = 75 = Number of units sold.
20 units were sold for 60$ so 55 units sold for 90$

Can someone explain where am i wrong here???
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Re: Another percent problem [#permalink] New post 28 Jul 2010, 20:33
amitjash wrote:
Please help me here... I get the answer 50. OA is definately correct or am i making some mistake please correct me where i am wrong.

20 articles for $60 means selling price = 3
20% profit is made so Cost Price = 2.5

Man has to incur a loss of 20% means he has to make a total loss of 20% and he sells X units in 90$

60+90 = 0.8 * (C.P. for 20+X units)
C.P. for 20+X units = 75*5/2

But the cost price for one unit is 2.5 so, 75*5/(2*2.5) = 75 = Number of units sold.
20 units were sold for 60$ so 55 units sold for 90$

Can someone explain where am i wrong here???


The loss of 20% in the second part of the question doesn't include the initial 20 items. It's just on the X number of items he needs to sell for a total of $90.
So 90=0.8(C.P of x units) So C.P of x units=$112.5 and since we know that C.P of each item is $2.5.
No of items he need to sell or x= 112.5/2.5 =45
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Re: A man sold 20 articles for $60 and gained 20%. How many [#permalink] New post 14 Jan 2014, 12:18
rxs0005 wrote:
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $90 to incur a loss 20%?

A. 45
B. 36
C. 40
D. 50
E. 48



I think my approach was somewhat different.

60 = 6/5x , so x = 50

That's total cost

So then 50/20 = 5/2 that's cost per article

Now then, 90/x = 5/2 (4/5)

x = # of articles

X = 45

A is the best answer

Cheers!
J :)
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Re: A man sold 20 articles for $60 and gained 20%. How many [#permalink] New post 16 Jan 2014, 21:01
c=cost per item
q=quantity of items

20%gain
60/20c=1.2
c=3/1.2

20%loss
90/(3/1.2)*q=.8
90=(2.4/1.2)q
q=45
Re: A man sold 20 articles for $60 and gained 20%. How many   [#permalink] 16 Jan 2014, 21:01
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