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Re: Another percent problem [#permalink]
28 Jul 2010, 15:55
rxs0005 wrote:
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $90 to incur a loss 20%?
A. 45
B. 36
C. 40
D. 50
E. 48
If he sells 20 articles for $60 then selling price for each article is $3. Since he gained 20% ,If the production cost per article is x then x*1.2=3 ==> x=$2.5 If a selling price of $90 for y articles makes a 20% loss then production price for those y articles is 90/.08 = 112.5 Since each article costs 2.5, y*2.5 =112.5 ==> y=45 _________________
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Re: Another percent problem [#permalink]
28 Jul 2010, 20:33
amitjash wrote:
Please help me here... I get the answer 50. OA is definately correct or am i making some mistake please correct me where i am wrong.
20 articles for $60 means selling price = 3 20% profit is made so Cost Price = 2.5
Man has to incur a loss of 20% means he has to make a total loss of 20% and he sells X units in 90$
60+90 = 0.8 * (C.P. for 20+X units) C.P. for 20+X units = 75*5/2
But the cost price for one unit is 2.5 so, 75*5/(2*2.5) = 75 = Number of units sold. 20 units were sold for 60$ so 55 units sold for 90$
Can someone explain where am i wrong here???
The loss of 20% in the second part of the question doesn't include the initial 20 items. It's just on the X number of items he needs to sell for a total of $90. So 90=0.8(C.P of x units) So C.P of x units=$112.5 and since we know that C.P of each item is $2.5. No of items he need to sell or x= 112.5/2.5 =45 _________________
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Re: A man sold 20 articles for $60 and gained 20%. How many [#permalink]
16 Jan 2015, 21:08
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