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# A manikin stands on a conic sugar loaf with height of 12 cm.

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Director
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A manikin stands on a conic sugar loaf with height of 12 cm. [#permalink]  26 Jan 2006, 02:38
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A manikin stands on a conic sugar loaf with height of 12 cm. If he runs down the sugar loaf at a constant speed of one centimetre per second, approximately how long will it last till he reaches table the loaf is standing on.

4,5,6,7 or 8 seconds?

To clarify:
conical is meant to be isoceles

Last edited by allabout on 26 Jan 2006, 02:51, edited 1 time in total.
Director
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Re: PS - general concept training - mixed [#permalink]  26 Jan 2006, 02:45
allabout wrote:
A manikin stands on a conic sugar loaf with height of 12 cm. If he runs down the sugar loaf at a constant speed of one centimetre per second, approximately how long will it last till he reaches table the loaf is standing on.

4,5,6,7 or 8 seconds?

allabout are you sure that there is no typo?I have a feeling that some info is missing))
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[#permalink]  26 Jan 2006, 11:43
My 200th post...I never new that I would last this long

Something is missing here. How long does it last ?

Since the conical is isoceles, it has to travel a distance equal to the hyptoneuse 12*sqrt(2) which gives around 16.8 seconds. To find the answer we need the decay rate.
Director
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[#permalink]  26 Jan 2006, 13:52
That's the question I think of, nothing more

The answers given were wrong, sorry for that inconvenience.

The height is 12

the hypotenuse is 12/sqrt 3 * 2 = ~ 14 cm

Thus it lasts ~14 seconds till he reaches the base of the loaf. Maybe the "sugar loaf" isn't the same in Germany as elsewhere.
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CEO
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[#permalink]  26 Jan 2006, 14:45
I don't agree with this.
In the figure below:

Height = CD = 12 cm
AB could be anything. Say AB = 10 then BC or AC = 13 and may be anything depending on the value of AB.

Please correct me if I am wrong...
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Director
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[#permalink]  26 Jan 2006, 21:49
allabout wrote:
That's the question I think of, nothing more

The answers given were wrong, sorry for that inconvenience.

The height is 12

the hypotenuse is 12/sqrt 3 * 2 = ~ 14 cm

Thus it lasts ~14 seconds till he reaches the base of the loaf. Maybe the "sugar loaf" isn't the same in Germany as elsewhere.

allabout please explain how did you figure out that hypotenuse is 12/sqrt 3 * 2 without knowing the lenght of second side?
As ps_dahiya said befor it could be anything
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Director
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[#permalink]  27 Jan 2006, 00:15
Since the triangle is isoceles (not equilateral), half of it is a 1:sqrt3:2 triangle

Accordingly you can divide the height by sqrt3.

Am I wrong?
[#permalink] 27 Jan 2006, 00:15
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# A manikin stands on a conic sugar loaf with height of 12 cm.

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