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# A merchant paid $300 for a shipment of x identical  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Eternal Intern Joined: 07 Jun 2003 Posts: 473 Location: Lone Star State Followers: 1 Kudos [?]: 44 [0], given: 0 A merchant paid$300 for a shipment of x identical  [#permalink]  24 Jul 2003, 20:55
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A merchant paid $300 for a shipment of x identical calculators. The merchant used 2 of the calculators as demonstrators and sold each of the others for$5 more than the average (arithmetic mean) cost of the x calculators. If the total revenue from the sale of the calculators was $120 more than the cost of the shipment, how many calculators were in the shipment? Manager Joined: 03 Jun 2003 Posts: 84 Location: Uruguay Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] 25 Jul 2003, 11:25 If I don┬┤t get it wrong, you have$120 as net result and you charged $5 above cost for each calculator, so 120/5 = 24 24+2 = 26 (as there were 2 for marketing) Director Joined: 03 Jul 2003 Posts: 656 Followers: 2 Kudos [?]: 22 [0], given: 0 [#permalink] 25 Jul 2003, 11:52 Ans: 30? X * C = 300 (X-2) * (C+5) = 300 + 120 Solving these equations, X = 30 Eternal Intern Joined: 07 Jun 2003 Posts: 473 Location: Lone Star State Followers: 1 Kudos [?]: 44 [0], given: 0 Hi [#permalink] 25 Jul 2003, 13:36 Kpadama-- that is two variables with one equation- that is not legitimate. VT Director Joined: 03 Jul 2003 Posts: 656 Followers: 2 Kudos [?]: 22 [0], given: 0 [#permalink] 25 Jul 2003, 14:08 Well ! I also fell into the same trap Look closely and you will see two. Eternal Intern Joined: 07 Jun 2003 Posts: 473 Location: Lone Star State Followers: 1 Kudos [?]: 44 [0], given: 0 [#permalink] 25 Jul 2003, 18:12 True, but solving equation takes along time, is there a better way here? Eternal Intern Joined: 07 Jun 2003 Posts: 473 Location: Lone Star State Followers: 1 Kudos [?]: 44 [0], given: 0 Victor [#permalink] 26 Jul 2003, 14:40 Anyone know how to factor this out quickly to solve? Director Joined: 25 Oct 2008 Posts: 610 Location: Kolkata,India Followers: 9 Kudos [?]: 288 [0], given: 100 Re: PS: Tough Algebra [#permalink] 11 Jun 2009, 01:18 Let c be the cost of each calculator when shipment was bought. Let x be the number of calculators in the shipment Of x calculators, only (x-2) were sold. Setting up the equation: (x-2) * (c+5) = 120 + 300 Since c = 300/x 300 - 2*300/x + 5x -10 = 120 + 300 -2*300/x + 5x = 130 In order to save time, substitute the answer value randomly. Start with E, it clicks. So the answer is 30 (E). _________________ Intern Joined: 04 Mar 2008 Posts: 43 Followers: 0 Kudos [?]: 3 [0], given: 6 Re: PS: Tough Algebra [#permalink] 12 Jun 2009, 10:46 30 is the correct answer as equation solved gives you 2 values 30 and -4. Re: PS: Tough Algebra [#permalink] 12 Jun 2009, 10:46 Similar topics Replies Last post Similar Topics: A merchant paid$300 for a shipment of x identical 3 22 Mar 2008, 14:52
A merchant paid $300 for a shipment of x identical 4 25 Apr 2006, 12:19 A merchant paid$300 for a shipment of x identical 1 06 Apr 2006, 18:50
A merchant paid $300 for a shipment of x identical 2 26 Feb 2006, 09:41 A merchant paid$300 for a shipment of x identical calculato 1 03 Jun 2005, 00:55
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