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A merchant paid $300 for a shipment of x identical [#permalink] ### Show Tags 26 Feb 2006, 09:41 This topic is locked. If you want to discuss this question please re-post it in the respective forum. A merchant paid$300 for a shipment of x identical calculators.
The merchant used 2 of the calculators as demonstrators and sold
each of the others for $5 more than the average (arithmetic mean) cost of the x calculators. If the total revenue from the sale of the calculators was$120 more than the cost of the shipment, how many
calculators were in the shipment?
(A) 24
(B) 25
(C) 26
(D) 28
(E) 30
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Re: Problem Solving Help [#permalink]

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26 Feb 2006, 10:19
Avis wrote:
A merchant paid $300 for a shipment of x identical calculators. The merchant used 2 of the calculators as demonstrators and sold each of the others for$5 more than the average (arithmetic mean)
cost of the x calculators. If the total revenue from the sale of
the calculators was $120 more than the cost of the shipment, how many calculators were in the shipment? (A) 24 (B) 25 (C) 26 (D) 28 (E) 30 E. (300/x+5)(x-2) = 120+300 Instead of solving the equation substitute the answers for x. Try the easy one e) 30. ((300/30)+5)(30-2)=420 GMAT Club Legend Joined: 07 Jul 2004 Posts: 5062 Location: Singapore Followers: 30 Kudos [?]: 348 [0], given: 0 [#permalink] ### Show Tags 26 Feb 2006, 18:04 Average cost of the x calculators = 300/x Merchant sold (x-2) calculators at (300/x + 5) dollars Profit (x-2)(300/x + 5) - 300 = 120 (x-2)(300+5x)/x = 420 300x + 5x^2 - 600 - 10x = 420x 5x^2 -130x -600 = 0 x^2 - 26 - 120 = 0 (x-30)(x+4) = 0 x = 30 Ans E [#permalink] 26 Feb 2006, 18:04 Display posts from previous: Sort by # A merchant paid$300 for a shipment of x identical

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