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A merchant paid $300 for a shipment of x identical calculato [#permalink] ### Show Tags 03 Jun 2005, 00:55 00:00 Difficulty: (N/A) Question Stats: 0% (00:00) correct 0% (00:00) wrong based on 0 sessions ### HideShow timer Statistics This topic is locked. If you want to discuss this question please re-post it in the respective forum. A merchant paid$300 for a shipment of x identical calculators. The merchant used 2 of the calculators as demonstrators and sold each of the others for $5 more than the average (arithmetic mean) cost of the x calculators. If the total revenue from the sale of the calculators was$120 more than the cost of the shipment, how many calculators were in the shipment?
(A) 24
(B) 25
(C) 26
(D) 28
(E) 30
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03 Jun 2005, 01:31
The total amount paid was $300 for x calculators. The amount paid for each calculator = 300/x The amount each calculator was sold for = 300/x + 5 = (300+5x)/x The number of calculators sold = (x-2) Revenue earned = 300 + 120 = 420 Revenue earned = number of calculators sold * selling price of each calculator. Therefore: [(300+5x)/x]*(x-2) = 420 [(300+5x)(x-2)]/x=420 (300+5x)(x-2)=420x 300x+5x^2-600-10x=420x 5x^2-130x-600=0 5(x^2-26x-120)=0 x^2 - 26x - 120 = 0 (x - 30) (x - 4) = 0 x = 30 or -4 as it can't be -4, answer has to be 30. 03 Jun 2005, 01:31 Display posts from previous: Sort by # A merchant paid$300 for a shipment of x identical calculato

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