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# A milkman adds 5 liters of water to a certain quantity of

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A milkman adds 5 liters of water to a certain quantity of [#permalink]

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13 Mar 2008, 11:14
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A milkman adds 5 liters of water to a certain quantity of pure milk costing \$3/liter. He sells the mixture at the same price as before and makes a profit of 20%. What is the percentage of milk in the mixture?

a) 83.33
b) 93.33
c) 73.33
d) 55
e) 68

First of all, how awful is the milkman that would do such a thing?! more seriously, I am having trouble with this problem. I get 80% as the answer, so I would guess 83.33% since they are close. Can someone walk me through this?

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OA is A
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13 Mar 2008, 11:31
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It's 83.33%

Assuming x is the volume of milk...

x liters cost 3x
After adding water, x+5 liters were sold for 3(x+5)

So percentage profit = [3(x+5) - 3x]*100 / 3x which is equal to 20
Solving for x gives x=25

Percentage of x = 25*100/30 = 83.33%
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13 Mar 2008, 11:37
I think I am still missing something. Sometimes these problems get you so hung up you cannot see them clearly.
Is the 30 the 25M+5W? Just double checking
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13 Mar 2008, 11:50
forget it, i answered my own silly question.

Re: Milkman Mixture   [#permalink] 13 Mar 2008, 11:50
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