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A motorcyclist has to cover a distance of 200 km to reach [#permalink]

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16 Aug 2011, 18:46

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Question Stats:

15% (03:18) correct
85% (03:09) wrong based on 13 sessions

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A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A. 50KM,60KM B. 40KM, 40KM C. 60KM, 30KM D. 50KM, 50 KM E. 60KM 60KM

A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A) 50KM,60KM B) 40KM, 40KM C)60KM, 30KM D)50KM, 50 KM E) 60KM 60KM

This is beyond GMAT because it is more laborious and less logical.

Let the initial breakdown occurred at x km Let the initial speed be v km/h

A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

we can use options to solve this poblem.

D) 50 KM , 50 KM

Ist part says if he travels 3/4 th of original speed he reaches 1 hour late.

3/4 th speed of 50 = 37.5

if 50 KM is already covered as in option, total time taken at reduced speed to cover remaining distance.

150 / 37.5 = 4 total time = 4 + 1 = 5

and if he has travelled at original speed , time taken = 200/ 50 = 4

Thus, the difference = 1 hour. In all the remaining case the difference of time is not 1 hour.

A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A) 50KM,60KM B) 40KM, 40KM C)60KM, 30KM D)50KM, 50 KM E) 60KM 60KM

This is beyond GMAT because it is more laborious and less logical.

Let the initial breakdown occurred at x km Let the initial speed be v km/h

This is the advantage of multiple choice questions...)

The first equation gives \(3v+x=200.\) The second equation boils down to \(18v+5x=1150.\) You can try to pick the correct answer based on the first equation and even before you work out the second equation. They can't be so mean to provide more than one solution which fulfill the first equation. Or let's hope...)
_________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: A motorcyclist has to cover a distance of 200 km to reach [#permalink]

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26 Nov 2013, 12:52

cleetus wrote:

A motorcyclist has to cover a distance of 200 km to reach city B from city A. After travelling a certain distance, his motorcycle develops a problem and travels at 3/4th of its original speed, there by he reached B 1 hour late. Had the problem developed 30 KM earlier, he would have reached b 12 mins later. Find the the initial distance traveled without the problem and the speed over that part of the journey.

A. 50KM,60KM B. 40KM, 40KM C. 60KM, 30KM D. 50KM, 50 KM E. 60KM 60KM

This is not GMAT material Cheers J

gmatclubot

Re: A motorcyclist has to cover a distance of 200 km to reach
[#permalink]
26 Nov 2013, 12:52

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