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A movie theater regularly sells adult tickets for $12 and child ticket

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Bunuel
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A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   01 Nov 2019, 06:41
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66% (03:09) correct 34% (03:27) wrong based on 293 sessions
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A movie theater regularly sells adult tickets for $12 and child tickets for $6. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend. If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

(A) 12%
(B) 10%
(C) 8%
(D) 5%
(E) 2%

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Kinshook
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A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   30 Mar 2020, 11:05
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Bunuel wrote:
A movie theater regularly sells adult tickets for $12 and child tickets for $6. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend. If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

(A) 12%
(B) 10%
(C) 8%
(D) 5%
(E) 2%

Are You Up For the Challenge: 700 Level Questions


Given:
1. A movie theater regularly sells adult tickets for $12 and child tickets for $6.
2. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend.

Asked: If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

Let the discount rate on adult movie ticket be x%
The discount rate on child ticket will be (15 - x)%

Total discount of 3 adults and 8 children tickets = 3*12*x + 6*8*(15%-x) = 6
6x + 8(15%-x) = 1
6x + 1.2 - 8x = 1
2x = .2
x = .2/2 = 10%

IMO B
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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   01 Nov 2019, 12:53
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Let D1 be discount percentage for adults and D2 be discount percentage for children.

We know that D1% + D2% = 15%
And

3*(1- D1%)*12 + 8*(1- D2%)*6 = 7800%
Solve for D1 = 10

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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   01 Nov 2019, 13:14
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Let there is x% discount on Adult tickets, and y% on child tickets

(12*3)*{x/100}+(6*8)(y/100)=6.......(1)

Also, x+y=15......(2)

From (1) and (2), we get
x=10
and y=5




Bunuel wrote:
A movie theater regularly sells adult tickets for $12 and child tickets for $6. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend. If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

(A) 12%
(B) 10%
(C) 8%
(D) 5%
(E) 2%

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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   10 Jun 2020, 22:18
Kinshook wrote:
Bunuel wrote:
A movie theater regularly sells adult tickets for $12 and child tickets for $6. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend. If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

(A) 12%
(B) 10%
(C) 8%
(D) 5%
(E) 2%

Are You Up For the Challenge: 700 Level Questions


Given:
1. A movie theater regularly sells adult tickets for $12 and child tickets for $6.
2. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend.

Asked: If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

Let the discount rate on adult movie ticket be x%
The discount rate on child ticket will be (15 - x)%

Total discount of 3 adults and 8 children tickets = 3*12*x + 6*8*(15%-x) = 6
6x + 8(15%-x) = 1
6x + 1.2 - 8x = 1
2x = .2
x = .2/2 = 10%

IMO B


I'm a little confused here. Question says that the discounted rate would be $6 dollars less than what they normally spend, so wouldnt the first equation be 3*12*x + 6*8*(15%-x) = 78? 78 is 6 less than the normal price for all of the tickets of $84
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Thekingmaker
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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   08 Jun 2021, 06:38
lenghty just solve the equations 6+ 12(1-0.0x)3 + 6(1-0.0y)8 =84 and 0.0x + 0.0y =0.15 and solve for X and we get 10
IMO B
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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink] New post   23 Jun 2022, 14:32
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Bunuel wrote:
A movie theater regularly sells adult tickets for $12 and child tickets for $6. On a certain day, the theater discounts these regular ticket prices at different rates so that a group of 3 adults and 8 children spends a total of $6 less than what it would regularly spend. If the sum of the two discount rates is 15%, what is the discount rate on each adult movie ticket?

(A) 12%
(B) 10%
(C) 8%
(D) 5%
(E) 2%



We can also just Plug In The Answers (PITA).
I like trying B and D and those look like the easiest to work with, so we are in good shape.

3 adults at $12 each + 8 children at $6 each costs $36 + $48 = $84 regularly.

B: 3 adults at $10.80 each + 8 children at $5.70 each costs $32.40 + $45.60 = $78.
Is that what we wanted? Yep.

Answer choice B.


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Re: A movie theater regularly sells adult tickets for $12 and child ticket [#permalink]
23 Jun 2022, 14:32
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