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A necklace is made by stringing N individual beads together

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A necklace is made by stringing N individual beads together [#permalink] New post 02 Nov 2006, 06:41
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A
B
C
D
E

Difficulty:

  25% (low)

Question Stats:

77% (01:00) correct 22% (00:51) wrong based on 54 sessions
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal

A. 16
B. 32
C. 41
D. 54
E. 68
[Reveal] Spoiler: OA
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 [#permalink] New post 02 Nov 2006, 06:57
The number of beads should fulfill N=5*K+3 .
Seems like E
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Re: PS Series [#permalink] New post 02 Nov 2006, 06:57
GMATT73 wrote:
A necklace is made by stringing N individual beads together in the repeating pattern red, green, white, blue and yellow. If the necklace begins with a red bead and ends with a white bead, then N could equal...

a. 16
b. 32
c. 41
d. 54
e. 68


there are 5 colors that repeat. so total beads=5k(number of repeated beads)+3(red, green, white)

basically, we have to find a number that is 3 more than a multiple of 5.

e.68 is the only number 65+3=68
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Re: [#permalink] New post 01 May 2013, 18:06
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GMATT73 wrote:
There must a simple equation to aplly here, just need a little help setting it up. Counting by brute force is a time waster!


A fast way without heavy calculations is to look at the answers and subtract 3 from the answer, and find if its a multiple of 5. Only option that fits this criteria is E.
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Re: A necklace is made by stringing N individual beads together [#permalink] New post 02 May 2013, 03:09
Expert's post
GMATT73 wrote:
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal

A. 16
B. 32
C. 41
D. 54
E. 68


Similar question to practice: 12-easy-pieces-or-not-126366.html#p1033936
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Re: A necklace is made by stringing N individual beads together   [#permalink] 02 May 2013, 03:09
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