A number is to be selected at random from the set above

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A number is to be selected at random from the set above [#permalink]

01 May 2012, 02:30

00:00

Question Stats:

66% (02:06) correct

33% (00:46) wrong

based on 15 sessions

{-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}

A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x-5)(x+10)(2x-5) = 0?

A. 1/12
B. 1/6
C. 1/4
D. 1/3
E. 1/2

[Reveal] Spoiler: OA

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Last edited by Bunuel on 01 May 2012, 02:41, edited 1 time in total.

Edited the question and added the OA

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Re: A number is to be selected at random from the set above [#permalink]

01 May 2012, 02:44

Stiv wrote:

Roots of the equation (x-5)(x+10)(2x-5)=0 are x=5, x=-10 and x=5/2=2.5. So, two solutions present in our set of 12 distinct numbers, therefore P=2/12=1/6.

Answer: B.
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Manager

Joined: 16 Feb 2012

Posts: 219

Concentration: Finance, Economics

Followers: 4

Kudos [?]: 19 [0], given: 93

Re: A number is to be selected at random from the set above [#permalink]

02 May 2012, 00:39

Aaaaaa OMG, I actually didn't notice that there isn't number 5(positive) in this bunch of numbers. I assumed it, and I got it wrong!

My advice to everyone: Don't assume anything!!!

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Re: A number is to be selected at random from the set above [#permalink] 02 May 2012, 00:39

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A number is to be selected at random from the set above

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