Last visit was: 24 Apr 2024, 10:37 It is currently 24 Apr 2024, 10:37

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618777 [33]
Given Kudos: 81588
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618777 [12]
Given Kudos: 81588
Send PM
avatar
Intern
Intern
Joined: 03 Mar 2015
Posts: 3
Own Kudos [?]: 6 [5]
Given Kudos: 61
Send PM
General Discussion
Manager
Manager
Joined: 12 Nov 2014
Posts: 126
Own Kudos [?]: 14 [3]
Given Kudos: 15
Concentration: General Management, Strategy
Send PM
Re: A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5 [#permalink]
3
Kudos
Answer is D (8)

Parabola y= ax^2+bx+c

x intercept at (-4,0) then 16a-4b+c=0 <=> c =4b-16a (1)
Vertex (-b/2a;c- b^2/4a)=(2,5) then -b/2a=2 <=> b=- 4a (2)
(1)+(2)=> c=8b (3)
c- b^2/4a = 5 (4)
From (2)(3)(4) we have 8b- b^2/(-b)=5 <=> 9b= 5 then b =5/9 then c =40/9 and a = -5/36
the second intercept x we have -5/36 x^2+ 5/9x+40/9=0
<=> x^2-4x-32=0
Using back solving,we have x =8; 8^2-4*8-32=0
Manager
Manager
Joined: 12 Nov 2014
Posts: 126
Own Kudos [?]: 14 [0]
Given Kudos: 15
Concentration: General Management, Strategy
Send PM
Re: A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5 [#permalink]
awanish1r wrote:
Parabola is symmetric about a line parallel to Y axis in this case. Therefore the X -coordinate distance of the other intercept is same from the vertex as the given intercept. The distance = 2-(-4)=6 , There the other coordinate is 2+6 = 8.

u are right. my way is silly :( too many years not study math sense is lost :(
Senior Manager
Senior Manager
Joined: 04 Jun 2016
Posts: 484
Own Kudos [?]: 2333 [0]
Given Kudos: 36
GMAT 1: 750 Q49 V43
Send PM
Re: A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5 [#permalink]
Bunuel wrote:
A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5), find the other x-intercept.

A. 5
B. 6
C. 7
D. 8
E. 9


Kudos for a correct solution.


The coordinates makes it clear that we are dealing with a parabola like a "inverted U" or a "straight A"

One arm of the parabola is cutting the x axis at -4, the vortex is 2 the distance between the arm and vortex is 6 units .
THE OTHER ARM WILL BE A MIRROR IMAGE OF THE FIRST ARM... AN IMAGINARY VERTICAL LINE DRAWN THROUGH THE VORTEX WILL ACTS AS THE AXIS OF SYMMETRY.
The vortex is at x=2. Now the other arm will be 6 unit away from x=2
There fore the other arm will be at X=2+6 = 8
The x coordinate of the other arm will be 8

ANSWER IS D
Manager
Manager
Joined: 03 Jul 2017
Status:IF YOU CAN DREAM IT, YOU CAN DO IT
Posts: 147
Own Kudos [?]: 33 [0]
Given Kudos: 27
Location: India
Concentration: Finance, International Business
Send PM
Re: A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5 [#permalink]
The point of vertex is the midpoint for the parabola and hence we can consider the midpoint formula to calculate the other interscept. Am i correct in my concept . Kindly help.
Director
Director
Joined: 13 Mar 2017
Affiliations: IIT Dhanbad
Posts: 628
Own Kudos [?]: 589 [1]
Given Kudos: 88
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE:Engineering (Energy and Utilities)
Send PM
Re: A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5 [#permalink]
1
Kudos
Bunuel wrote:
A parabola has one x-intercept at (– 4, 0). If the vertex is at (2, 5), find the other x-intercept.

A. 5
B. 6
C. 7
D. 8
E. 9


Kudos for a correct solution.


Vertex of the parabola is (2,5) . The x coordinate is 2.
So parabola is symmetrical about x =2

Parabola has x - intercept as (-4,0 ). Sodistance between x =2 and x-inctercept of arabola = 2-(-4) = 6
other x - intercept = (2+6,0) = (8.0)


Answer D
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32648
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: A parabola has one x-intercept at ( 4, 0). If the vertex is at (2, 5 [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: A parabola has one x-intercept at ( 4, 0). If the vertex is at (2, 5 [#permalink]
Moderators:
Math Expert
92902 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne