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A person purchased a total of 2t + 1 tickets. Some cost $4

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A person purchased a total of 2t + 1 tickets. Some cost $4 [#permalink] New post 06 Aug 2003, 08:45
A person purchased a total of 2t + 1 tickets. Some cost $4 the remaining cost $7. If 3 more $ 4 than $7 tickets were purchased. what equation can express, the total cost in dollars of the 2t + 1 tickets?

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 [#permalink] New post 06 Aug 2003, 09:07
total# of tickets = 2t+1

let, x = # of $7 tickets
so, x+3 = # of $4 tickets

So, total # of tickets in terms of x = 2x+3

so, 2x+3 = 2t+1
=> x = t-1 ---> # of $7 tickets

so, x+3 = t+2 ---> # of $4 tickets

So, total $ amount = 7(t-1) + 4(t+2) = 11t+1 dollars

Last edited by prakuda2000 on 06 Aug 2003, 12:29, edited 1 time in total.
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Hi [#permalink] New post 06 Aug 2003, 11:57
3 more $ 4 than $7 tickets were purchased.

Looks like you got that wrong, Prakunda,
I still think it can only be solved with picking numbers.

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 [#permalink] New post 06 Aug 2003, 12:30
Yes, I corrected the $4, $7 ticket. See changed solution
  [#permalink] 06 Aug 2003, 12:30
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A person purchased a total of 2t + 1 tickets. Some cost $4

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