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A person purchased a total of 2t + 1 tickets. Some cost $4 [#permalink] ### Show Tags 06 Aug 2003, 08:45 This topic is locked. If you want to discuss this question please re-post it in the respective forum. A person purchased a total of 2t + 1 tickets. Some cost$4 the remaining cost $7. If 3 more$ 4 than $7 tickets were purchased. what equation can express, the total cost in dollars of the 2t + 1 tickets? Victor _________________ Ride em cowboy Manager Joined: 22 Jul 2003 Posts: 62 Location: CA Followers: 1 Kudos [?]: 0 [0], given: 0 [#permalink] ### Show Tags 06 Aug 2003, 09:07 total# of tickets = 2t+1 let, x = # of$7 tickets
so, x+3 = # of $4 tickets So, total # of tickets in terms of x = 2x+3 so, 2x+3 = 2t+1 => x = t-1 ---> # of$7 tickets

so, x+3 = t+2 ---> # of $4 tickets So, total$ amount = 7(t-1) + 4(t+2) = 11t+1 dollars

Last edited by prakuda2000 on 06 Aug 2003, 12:29, edited 1 time in total.
Eternal Intern
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06 Aug 2003, 11:57
3 more $4 than$7 tickets were purchased.

Looks like you got that wrong, Prakunda,
I still think it can only be solved with picking numbers.

Victor
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Ride em cowboy

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06 Aug 2003, 12:30
Yes, I corrected the $4,$7 ticket. See changed solution
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