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A person sells clothes. At the price of $20, he can sell 100 [#permalink] ### Show Tags 04 Aug 2006, 22:55 00:00 Difficulty: (N/A) Question Stats: 0% (00:00) correct 0% (00:00) wrong based on 0 sessions ### HideShow timer Statistics This topic is locked. If you want to discuss this question please re-post it in the respective forum. A person sells clothes. At the price of$20, he can sell 100 clothes. For each dollar the price decreases, 10 more clothes will be sold. What can be his maximun revenue to obtain?
A. 2000
B. 2240
C. 2250
D. 2270
E. 2300
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Last edited by freetheking on 05 Aug 2006, 00:20, edited 2 times in total.
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04 Aug 2006, 23:52
20*100=2000
19*110=2090
18*120=2160
17*130=2210
16*140=2240
15*150=2250
14*160=2240
so at price of 15 the revenue would be max 2250
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05 Aug 2006, 00:13

F(n) = (20-n)(100+10n)

F(n) = 2000+100n-10n^2
= -10(n^2-10n-200)
= -10[(n-5)^2-225] (concave down.. when n=5 maximun value)

F(5) = -10*-225 = 2250
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Last edited by freetheking on 05 Aug 2006, 00:21, edited 1 time in total.
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05 Aug 2006, 00:16
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05 Aug 2006, 13:25
freetheking wrote:
A person sells clothes. At the price of $20, he can sell 100 clothes. For each dollar the price decreases, 10 more clothes will be sold. What can be his maximun revenue to obtain? A. 2000 B. 2240 C. 2250 D. 2270 E. 2300 @$20 Revenue =2000
@ $19 Revenue =2090 (19*110) @$18 Revenue =2160 (18*120)
@ $17 Revenue =2210 (17*130) @$16 Revenue =2240 (16*140)