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# A person who runs at 80 mph starts at 8.00, after half an

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21 Apr 2006, 02:28
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A person who runs at 80 mph starts at 8.00, after half an hour, another person runs for the same direction at a speed 1/4 more than previous one, when will he overtake the previous one?

A. 8:30
B. 9.00
C. 9.30
D. 10.00
E. 10.30
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21 Apr 2006, 02:49

I attack this kind of questions in the following manner....

1st runner runs at 80mph per hour
2nd runner 1/4 faster, so 100 mph.....

1st runner starts to run at 8:00
2nd runner at 8:30

During the haf an hour 1st runner will run 40 miles...
2nd runner runs 20 miles per hour faster than the 1st one.... So he will catch the 1st runner in 2 hours.....

Starts at 8:30 + 2 h=10:30

For me it is a very quick approach...
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21 Apr 2006, 04:54
First runner,
Speed = 80
Time = t

Second runner,
Speed = 5/4 * 80 = 100
Time = t-.5

Distance is same in both cases
80t = 100(t-.5)
Solving, t = 2.5

From 8.00, 2.5 hrs later is 10.30.
Hence E
21 Apr 2006, 04:54
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# A person who runs at 80 mph starts at 8.00, after half an

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