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Re: A produce stand sells green peppers for a certain price and red pepper [#permalink]
1
Kudos
Here we go---

Let price of Red Pepper = r
Let price of Green Pepper = g

2g + 3r = ???


St1:

6g + 9r = 12 ---(1) divide the eq by 3

2g + 3r = 4 (that is what we want)

Clearly sufficient


St2:

4g + 3r = 5

There can be multiple values for g and r.

Clearly not sufficient.

Option A is correct
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Re: A produce stand sells green peppers for a certain price and red pepper [#permalink]
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Bunuel wrote:
A produce stand sells green peppers for a certain price and red peppers for a different price. If Nick, Katie, and Alyssa bought peppers at the stand, how much did Alyssa pay for 2 green peppers and 3 red peppers?

(1) Nick bought 6 green peppers and 9 red peppers for $12.00.
(2) Katie bought 4 green peppers and 3 red peppers for $5.00.

Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION:

Correct Answer: A

Let g be the price for each green pepper, and r be the price for each red pepper. Statement (1) lets us express Nick's purchase as 6g + 9r = $12.00. Normally, since we only have one equation and two variables, we would not be able to solve this. However, note that this is the same equation as the one stated in the question: Nick simply purchased 3 times as many peppers (of each type) as did Alyssa, and $12.00/3 = $4.00, so Statement (1) is sufficient. Statement (2) is equivalent to 4g + 3r = $5.00. Here we have one equation and two variables, but this equation is not a multiple of the original equation like the equation in statement (1); not sufficient.
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Re: A produce stand sells green peppers for a certain price and red pepper [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A produce stand sells green peppers for a certain price and red pepper [#permalink]
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