Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:21

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

35% (medium)

Question Stats:

58% (02:38) correct
42% (02:18) wrong based on 71 sessions

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?

Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:33

1

This post received KUDOS

aparnaharish wrote:

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %

let say T car travel 100 miles with 100 $ gasoline therefore according to quest P car will travell 180(80%more) mile and gasoline cost will be 120(20%more)

therfore p car will travel 100 miles in (120/180)*100 $= 200/3 $

difference of money for both cars travelling for 100 miles = 100-(200/3) = 100/3

so percentage less will be ((100/3)/100)*100 (DENOMINATOR IS 100 as cost for T was 100 $...and multiplying by 100 in order to take out the percent value) = 33 1/3

hence B _________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:37

miles=gallons*MPG.

G_p*MPG_p=G_t*MPG_t with the data we know that G_p*1.8=G_t, \frac{G_p}{G_t}=\frac{1}{1.8}.

We know also that price_p=1.2*price_tso the cost is (price*number of gallons)\frac{P}{T}=\frac{Price_p}{Price_t}*\frac{G_p}{G_t}=\frac{1.2}{1.8}=\frac{2}{3} or 1/3 (33.3%) less. _________________

It is beyond a doubt that all our knowledge that begins with experience.

Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 23:24

2

This post received KUDOS

Expert's post

aparnaharish wrote:

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %

Or you can plug in numbers:

P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon.

P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs $1 per gallon, P-Car gasoline costs $1.2 per gallon.

T-Car runs 10 miles in $1 i.e. 180 miles in $18 P-Car runs 18 miles in $1.2 i.e. 180 miles in $12

P-Car costs (6/18)*100 = 33.33% less _________________

Re: A prototype fuel-efficient car (P-Car) [#permalink]
09 Aug 2013, 01:46

aparnaharish wrote:

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?

Re: A prototype fuel-efficient car (P-Car) [#permalink]
12 Aug 2013, 18:12

VeritasPrepKarishma wrote:

aparnaharish wrote:

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %

Or you can plug in numbers:

P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon.

P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs $1 per gallon, P-Car gasoline costs $1.2 per gallon.

T-Car runs 10 miles in $1 i.e. 180 miles in $18 P-Car runs 18 miles in $1.2 i.e. 180 miles in $12

P-Car costs (6/18)*100 = 33.33% less

Hi VeritasPrepKarishma,

I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses $ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33%

Re: A prototype fuel-efficient car (P-Car) [#permalink]
12 Aug 2013, 20:32

1

This post received KUDOS

Expert's post

Diipz wrote:

Hi VeritasPrepKarishma,

I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses $ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33%

I don't see any problem here. You got the % difference as 1/3 which is 33.33%. This is the correct answer. _________________

Re: A prototype fuel-efficient car (P-Car) [#permalink]
30 May 2014, 12:34

Let's say that T car is driven at 10mpg while P car is driven at 18mpg.

Now, then Let's also assume that T car's gallon costs 10 bucks wihle P car gallon costs 12 bucks.

Finally, let's assume that the total distance is 180. Therefore P car will spend 120 and T car will spend 180. Therefore the difference is 60/180=33.3%.

Answer is B

Hope this helps

gmatclubot

Re: A prototype fuel-efficient car (P-Car)
[#permalink]
30 May 2014, 12:34