A prototype fuel-efficient car (P-Car) : GMAT Problem Solving (PS)
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# A prototype fuel-efficient car (P-Car)

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A prototype fuel-efficient car (P-Car) [#permalink]

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08 Aug 2013, 00:21
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A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3%
B) 33 1/3 %
C) 50%
D) 60%
E) 66 2/3 %
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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08 Aug 2013, 00:33
2
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aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3%
B) 33 1/3 %
C) 50%
D) 60%
E) 66 2/3 %

let say T car travel 100 miles with 100 $gasoline therefore according to quest P car will travell 180(80%more) mile and gasoline cost will be 120(20%more) therfore p car will travel $$100$$ miles in $$(120/180)*100$$$= $$200/3$$ $difference of money for both cars travelling for 100 miles = 100-(200/3) = 100/3 so percentage less will be ((100/3)/100)*100 (DENOMINATOR IS 100 as cost for T was 100$...and multiplying by 100 in order to take out the percent value)
= 33 1/3

hence B
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Last edited by blueseas on 08 Aug 2013, 00:34, edited 1 time in total.
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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08 Aug 2013, 00:33
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Assumption

Miles/Gallon
T = 100
P = 180 ( 80% more)

$/gallon T = 100 P = 120 (20% more) Miles 100 for both Cost = (Miles X$/ Gallon)/ M/gallon

T = 100
P = 66.67

Hence 100 - 66.67 = 33.3 = 33 1/3%

Ans B

Consider Kudos for explanation
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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08 Aug 2013, 00:37
$$miles=gallons*MPG$$.

$$G_p*MPG_p=G_t*MPG_t$$ with the data we know that $$G_p*1.8=G_t$$, $$\frac{G_p}{G_t}=\frac{1}{1.8}$$.

We know also that $$price_p=1.2*price_t$$so the cost is (price*number of gallons)$$\frac{P}{T}=\frac{Price_p}{Price_t}*\frac{G_p}{G_t}=\frac{1.2}{1.8}=\frac{2}{3}$$ or 1/3 (33.3%) less.
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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08 Aug 2013, 23:24
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Expert's post
aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3%
B) 33 1/3 %
C) 50%
D) 60%
E) 66 2/3 %

Or you can plug in numbers:

P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon.

P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs $1 per gallon, P-Car gasoline costs$1.2 per gallon.

T-Car runs 10 miles in $1 i.e. 180 miles in$18
P-Car runs 18 miles in $1.2 i.e. 180 miles in$12

P-Car costs (6/18)*100 = 33.33% less
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Senior Manager Joined: 10 Jul 2013 Posts: 335 Followers: 3 Kudos [?]: 312 [0], given: 102 Re: A prototype fuel-efficient car (P-Car) [#permalink] ### Show Tags 09 Aug 2013, 01:46 aparnaharish wrote: A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car? A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 % .......... solution: (1-2/3)/1 * 100 = 33.33% _________________ Asif vai..... Intern Joined: 20 Mar 2013 Posts: 4 Followers: 0 Kudos [?]: 5 [0], given: 10 Re: A prototype fuel-efficient car (P-Car) [#permalink] ### Show Tags 12 Aug 2013, 18:12 VeritasPrepKarishma wrote: aparnaharish wrote: A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car? A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 % Or you can plug in numbers: P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon. P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs$1 per gallon, P-Car gasoline costs $1.2 per gallon. T-Car runs 10 miles in$1 i.e. 180 miles in $18 P-Car runs 18 miles in$1.2 i.e. 180 miles in $12 P-Car costs (6/18)*100 = 33.33% less Hi VeritasPrepKarishma, I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses$ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33% Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7131 Location: Pune, India Followers: 2140 Kudos [?]: 13711 [1] , given: 222 Re: A prototype fuel-efficient car (P-Car) [#permalink] ### Show Tags 12 Aug 2013, 20:32 1 This post received KUDOS Expert's post Diipz wrote: Hi VeritasPrepKarishma, I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses$ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33% I don't see any problem here. You got the % difference as 1/3 which is 33.33%. This is the correct answer. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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30 May 2014, 12:34
Let's say that T car is driven at 10mpg while P car is driven at 18mpg.

Now, then Let's also assume that T car's gallon costs 10 bucks wihle P car gallon costs 12 bucks.

Finally, let's assume that the total distance is 180. Therefore P car will spend 120 and T car will spend 180. Therefore the difference is 60/180=33.3%.

Hope this helps
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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04 Oct 2015, 01:06
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Re: A prototype fuel-efficient car (P-Car) [#permalink]

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11 Nov 2016, 01:13
Hello from the GMAT Club BumpBot!

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Re: A prototype fuel-efficient car (P-Car)   [#permalink] 11 Nov 2016, 01:13
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