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A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:21
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Difficulty:
55% (hard)
Question Stats:
61% (02:53) correct
39% (02:39) wrong based on 108 sessions
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?
Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:33
1
This post received KUDOS
aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?
A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %
let say T car travel 100 miles with 100 $ gasoline therefore according to quest P car will travell 180(80%more) mile and gasoline cost will be 120(20%more)
therfore p car will travel \(100\) miles in \((120/180)*100\) $= \(200/3\) $
difference of money for both cars travelling for 100 miles = 100-(200/3) = 100/3
so percentage less will be ((100/3)/100)*100 (DENOMINATOR IS 100 as cost for T was 100 $...and multiplying by 100 in order to take out the percent value) = 33 1/3
hence B _________________
When you want to succeed as bad as you want to breathe ...then you will be successfull....
Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 00:37
\(miles=gallons*MPG\).
\(G_p*MPG_p=G_t*MPG_t\) with the data we know that \(G_p*1.8=G_t\), \(\frac{G_p}{G_t}=\frac{1}{1.8}\).
We know also that \(price_p=1.2*price_t\)so the cost is (price*number of gallons)\(\frac{P}{T}=\frac{Price_p}{Price_t}*\frac{G_p}{G_t}=\frac{1.2}{1.8}=\frac{2}{3}\) or 1/3 (33.3%) less. _________________
It is beyond a doubt that all our knowledge that begins with experience.
Re: A prototype fuel-efficient car (P-Car) [#permalink]
08 Aug 2013, 23:24
2
This post received KUDOS
Expert's post
aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?
A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %
Or you can plug in numbers:
P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon.
P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs $1 per gallon, P-Car gasoline costs $1.2 per gallon.
T-Car runs 10 miles in $1 i.e. 180 miles in $18 P-Car runs 18 miles in $1.2 i.e. 180 miles in $12
P-Car costs (6/18)*100 = 33.33% less _________________
Re: A prototype fuel-efficient car (P-Car) [#permalink]
09 Aug 2013, 01:46
aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?
Re: A prototype fuel-efficient car (P-Car) [#permalink]
12 Aug 2013, 18:12
VeritasPrepKarishma wrote:
aparnaharish wrote:
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two cars are driven the same distance, what percent less than the money spent on gasoline for the T-Car is the money spent on gasoline for the P-Car?
A) 16 2/3% B) 33 1/3 % C) 50% D) 60% E) 66 2/3 %
Or you can plug in numbers:
P-Car is estimated to get 80% more miles per gallon of gasoline than does a traditional fuel-efficient car (T-Car) - So if T-Car gets 10 miles per gallon, P-Car gets 18 miles per gallon.
P-Car requires a special type of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car - So if T-Car gasoline costs $1 per gallon, P-Car gasoline costs $1.2 per gallon.
T-Car runs 10 miles in $1 i.e. 180 miles in $18 P-Car runs 18 miles in $1.2 i.e. 180 miles in $12
P-Car costs (6/18)*100 = 33.33% less
Hi VeritasPrepKarishma,
I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses $ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33%
Re: A prototype fuel-efficient car (P-Car) [#permalink]
12 Aug 2013, 20:32
1
This post received KUDOS
Expert's post
Diipz wrote:
Hi VeritasPrepKarishma,
I solved exactly the same way as you did, however I am unable to calculate the percent difference. Car T - 10 miles and car P - 18 miles. I assumed the cost for one gallon as 20 for T and 24 for P . Hence for a distance of 100 miles, car T uses $ 200 and car P uses $400/3. But when I find the percent difference which is (200-400/3)/ 200 = 33%
I don't see any problem here. You got the % difference as 1/3 which is 33.33%. This is the correct answer. _________________
Re: A prototype fuel-efficient car (P-Car) [#permalink]
30 May 2014, 12:34
Let's say that T car is driven at 10mpg while P car is driven at 18mpg.
Now, then Let's also assume that T car's gallon costs 10 bucks wihle P car gallon costs 12 bucks.
Finally, let's assume that the total distance is 180. Therefore P car will spend 120 and T car will spend 180. Therefore the difference is 60/180=33.3%.
Re: A prototype fuel-efficient car (P-Car) [#permalink]
04 Oct 2015, 01:06
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