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A pub owner has three different kinds of beer of quantities

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A pub owner has three different kinds of beer of quantities [#permalink] New post 09 Jan 2004, 13:05
A pub owner has three different kinds of beer of quantities 82 litres, 123 litres, and 205 litres respectively. Find the least number of cannisters of equal size required to store all the beer without mixing.

a. 9
b. 10
c. 12
d. 15
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 [#permalink] New post 09 Jan 2004, 13:39
your answers are useless to us without reasoning
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 [#permalink] New post 09 Jan 2004, 13:56
10

82 = 2*41
123 = 3*41
205 = 5*41
Total is 2+3+5 cannisters of equal size (41liters)
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 [#permalink] New post 09 Jan 2004, 14:03
:good
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 [#permalink] New post 09 Jan 2004, 14:04
:good
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 [#permalink] New post 09 Jan 2004, 14:17
Why isn't it three?

The question does not state that the canisters must be filled to the rim.
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 [#permalink] New post 09 Jan 2004, 14:18
Stoolfi is doing some serious CR - Weaken the question lately :wink:
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 [#permalink] New post 09 Jan 2004, 14:26
:lol:
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 [#permalink] New post 10 Jan 2004, 09:26
82+123+205 = 410

this can be factorised as 41*10
So the minimum number of cans required to completely fill each can without mixing = 10

Again largest common factor among them is 41. The problem can be solved this way as well
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 [#permalink] New post 10 Jan 2004, 10:25
I see. But I still think it's better by breaking it down to factors. It's easier to see the 41 stand out. But for an accustomed eye, your way is sure easier
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 [#permalink] New post 10 Jan 2004, 13:05
I didn't like this problem. We could have a canister of 82 liters, and in that case the answer would be 5
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 [#permalink] New post 10 Jan 2004, 13:09
It cannot be 82 because it is not a common factor to 123 and 205...
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  [#permalink] 10 Jan 2004, 13:09
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A pub owner has three different kinds of beer of quantities

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