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A pub owner has three different kinds of beer of quantities [#permalink]
 09 Jan 2004, 14:05
A pub owner has three different kinds of beer of quantities 82 litres, 123 litres, and 205 litres respectively. Find the least number of cannisters of equal size required to store all the beer without mixing.
a. 9
b. 10
c. 12
d. 15
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****GMAT Loco****
Este examen me conduce jodiendo loco
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Senior Manager
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your answers are useless to us without reasoning
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Pls include reasoning along with all answer posts.
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10
82 = 2*41
123 = 3*41
205 = 5*41
Total is 2+3+5 cannisters of equal size (41liters)
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Best Regards,
Paul
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_________________
Pls include reasoning along with all answer posts.
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Este examen me conduce jodiendo loco
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_________________
Pls include reasoning along with all answer posts.
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Este examen me conduce jodiendo loco
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Director
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Why isn't it three?
The question does not state that the canisters must be filled to the rim.
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GMAT Club Legend
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Stoolfi is doing some serious CR - Weaken the question lately 
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Best Regards,
Paul
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Senior Manager
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_________________
Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco
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82+123+205 = 410
this can be factorised as 41*10
So the minimum number of cans required to completely fill each can without mixing = 10
Again largest common factor among them is 41. The problem can be solved this way as well
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GMAT Club Legend
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I see. But I still think it's better by breaking it down to factors. It's easier to see the 41 stand out. But for an accustomed eye, your way is sure easier
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Paul
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I didn't like this problem. We could have a canister of 82 liters, and in that case the answer would be 5
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Salvador aà vou eu!!!
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It cannot be 82 because it is not a common factor to 123 and 205...
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Paul
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