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# A pub owner has three different kinds of beer of quantities

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A pub owner has three different kinds of beer of quantities [#permalink]

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09 Jan 2004, 14:05
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A pub owner has three different kinds of beer of quantities 82 litres, 123 litres, and 205 litres respectively. Find the least number of cannisters of equal size required to store all the beer without mixing.

a. 9
b. 10
c. 12
d. 15
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Pls include reasoning along with all answer posts.
****GMAT Loco****
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09 Jan 2004, 14:39
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Pls include reasoning along with all answer posts.
****GMAT Loco****
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09 Jan 2004, 14:56
10

82 = 2*41
123 = 3*41
205 = 5*41
Total is 2+3+5 cannisters of equal size (41liters)
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Paul

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09 Jan 2004, 15:03

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Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

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09 Jan 2004, 15:04

_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

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09 Jan 2004, 15:17
Why isn't it three?

The question does not state that the canisters must be filled to the rim.
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09 Jan 2004, 15:18
Stoolfi is doing some serious CR - Weaken the question lately
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Paul

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09 Jan 2004, 15:26

_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

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10 Jan 2004, 10:26
82+123+205 = 410

this can be factorised as 41*10
So the minimum number of cans required to completely fill each can without mixing = 10

Again largest common factor among them is 41. The problem can be solved this way as well
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10 Jan 2004, 11:25
I see. But I still think it's better by breaking it down to factors. It's easier to see the 41 stand out. But for an accustomed eye, your way is sure easier
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Paul

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10 Jan 2004, 14:05
I didn't like this problem. We could have a canister of 82 liters, and in that case the answer would be 5
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10 Jan 2004, 14:09
It cannot be 82 because it is not a common factor to 123 and 205...
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Paul

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