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# A question from GMAT Club Test

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Manager
Joined: 13 Mar 2007
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A question from GMAT Club Test [#permalink]  06 Aug 2008, 17:44
If you know how to solve the following question and you know how to explain your answer, please let me know. By the way, I already found some explanations for this question, but I did not understand their explanations.

A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?
a)3
b)5
c)6
d)7
e)8

Director
Joined: 23 Sep 2007
Posts: 798
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Kudos [?]: 74 [0], given: 0

Re: A question from GMAT Club Test [#permalink]  06 Aug 2008, 18:08
Assuming that there are no 2 headed cats/sailors (like in recent news).

6 cats and 7 sailors

take out the captain and the cook, you have 13 heads and 38 legs

sailor + cat = 13 --> S = 13 -C

2 legs for each sailor and 4 legs for each cat.

2S + 4C = 38

2(13 - C) + 4C = 38
2C = 12
C = 6
S = 7
CEO
Joined: 29 Aug 2007
Posts: 2501
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Kudos [?]: 500 [0], given: 19

Re: A question from GMAT Club Test [#permalink]  06 Aug 2008, 18:31
GMAT_700 wrote:
If you know how to solve the following question and you know how to explain your answer, please let me know. By the way, I already found some explanations for this question, but I did not understand their explanations.

A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?
a)3
b)5
c)6
d)7
e)8

Q + cats + Sailors + a cook + a captain = 15
1 + cats + Sailors + 1 + 1 = 15
cats + Sailors = 12

2Q + 4(cats) + 2(Sailors) + 2 (a cook) + a captain = 41
2 + 4(cats) + 2(Sailors) + 2 + 1 = 41
4(cats) + 2(Sailors) = 36
2(cats) + (cats) + (Sailors) + (cats) + (Sailors) = 36
2(cats) + 12 + 12 = 36
cats + = (36 - 24)/2 = 12

So Cats = 6
_________________
Manager
Joined: 15 Jul 2008
Posts: 209
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Kudos [?]: 21 [0], given: 0

Re: A question from GMAT Club Test [#permalink]  07 Aug 2008, 04:03
Easier approach

cats + humans without captain = 14 (since only one captain is there)
let c= #of cats, h=#humans (non captain)

c+h=14

leg count.
4(c) + 2(h) = 40. Captain had only one leg
so 2c+h=20

solve to get c=6
SVP
Joined: 07 Nov 2007
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Location: New York
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Re: A question from GMAT Club Test [#permalink]  07 Aug 2008, 06:31
GMAT_700 wrote:
If you know how to solve the following question and you know how to explain your answer, please let me know. By the way, I already found some explanations for this question, but I did not understand their explanations.

A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?
a)3
b)5
c)6
d)7
e)8

heads 1 (cook) 1(captain) x(sailors) y(cats)
legs 2 (cook) 1(captain) 2x(sailors) 4 y(cats)

2+1+2x+4y= 41

solve above y=6
_________________

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VP
Joined: 17 Jun 2008
Posts: 1406
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Kudos [?]: 113 [0], given: 0

Re: A question from GMAT Club Test [#permalink]  07 Aug 2008, 16:48
x2suresh wrote:
GMAT_700 wrote:
If you know how to solve the following question and you know how to explain your answer, please let me know. By the way, I already found some explanations for this question, but I did not understand their explanations.

A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 15 heads and 41 legs. How many cats does the ship host?
a)3
b)5
c)6
d)7
e)8

heads 1 (cook) 1(captain) x(sailors) y(cats)
legs 2 (cook) 1(captain) 2x(sailors) 4 y(cats)

2+1+2x+4y= 41

solve above y=6

solved and got the same
_________________

cheers
Its Now Or Never

Re: A question from GMAT Club Test   [#permalink] 07 Aug 2008, 16:48
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