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A rabbit on a controlled diet is fed daily 300 grams of a

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A rabbit on a controlled diet is fed daily 300 grams of a [#permalink] New post 26 Jul 2007, 08:45
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50% (02:32) correct 50% (01:12) wrong based on 54 sessions
A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10% protein and food Y contains 15% protein. If the rabbit's diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture.

a)100
b)140
c)150
d)160
e)200

The answer is B)140, but I do not understand the OG explanation. Can someone provide their approach to this question in detail

Thanks,
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 [#permalink] New post 26 Jul 2007, 08:52
Set up two equations.

We know that 10%x+15%y=38 grams or .1x+.15y=38

We also know that x+y=300 grams.

2 eq. with 2 variables. Solve them and you should get it.
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 [#permalink] New post 26 Jul 2007, 08:55
In original Solution : X+Y= 300
Protein content : 0.1X+0.15Y=38

Solve these 2 equations and you will get the results.
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Re: Mixture Problem. Please explain [#permalink] New post 26 Jul 2007, 09:17
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tinman1412 wrote:
A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10% protein and food Y contains 15% protein. If the rabbit's diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture.

a)100
b)140
c)150
d)160
e)200

The answer is B)140, but I do not understand the OG explanation. Can someone provide their approach to this question in detail

Thanks,



in fact one eq is enough: .1x + .15(300-x) = 38

solve for x, x = 140
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Re: Mixture Problem. Please explain [#permalink] New post 26 Jul 2007, 09:23
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Himalayan wrote:
tinman1412 wrote:
A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10% protein and food Y contains 15% protein. If the rabbit's diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture.

a)100
b)140
c)150
d)160
e)200

The answer is B)140, but I do not understand the OG explanation. Can someone provide their approach to this question in detail

Thanks,



in fact one eq is enough: .1x + .15(300-x) = 38

solve for x, x = 140


A word from our efficiency expert :))
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Re: Mixture Problem. Please explain [#permalink] New post 26 Jul 2007, 09:35
tinman1412 wrote:
A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10% protein and food Y contains 15% protein. If the rabbit's diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture.

a)100
b)140
c)150
d)160
e)200

The answer is B)140, but I do not understand the OG explanation. Can someone provide their approach to this question in detail

Thanks,


Much simpler method is there...
38 gms means approx. 12.66%. Then use the mixture alligation formula to calculate the ratio of X to Y, ie,

X/Y= (15-12.66)/(12.66-10)=2.33/2.66.
Hence amt of X in total mixture is 300*2.33/(2.33+2.66)=139.2~140
Answer B.
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 [#permalink] New post 26 Jul 2007, 09:38
I've got to start looking at problems like that! :?
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 [#permalink] New post 26 Jul 2007, 10:16
D

Assume x grams is of mixture A and 300-x is of mixture B
Eqn is:

(300-x)*.1 + .15x = 38 (10% and 15% protein in Mixtures A and B respectively)

Solve for x =160
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 [#permalink] New post 26 Jul 2007, 18:00
I was just wondering. I know there are many different ways to solve math problems, but is there a prefer method when solving Mixture Problems?
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 [#permalink] New post 27 Jul 2007, 01:20
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0.1x + 0.15y = 38

x+y = 300
x = 300-y

so 0.1(300-y) + 0.15y = 38
30-0.1y + 0.15y = 38
0.05y = 8
y = 160 grams

then x = 140 grams.

Ans B
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 [#permalink] New post 27 Jul 2007, 04:35
tinman1412 wrote:
I was just wondering. I know there are many different ways to solve math problems, but is there a prefer method when solving Mixture Problems?


Its wat you feel comfortable with or the one which you do faster and accurately. You have to develop that approach by practice.
Atleast I think so. I solved the problem using Mixtures & Alligation formula coz I feel comfortable with that.

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Re: Mixture Problem. Please explain [#permalink] New post 13 Aug 2009, 02:34
wow great explanations here!
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Re: Mixture Problem. Please explain [#permalink] New post 13 Aug 2009, 04:37
MGMAT has a great method that has really helped me to do these problems quickly.

For mixture problems, set up a chart:

the two different mixtures go on the right hand side, the quantities of each go on the top:

Protein Other
X

Y

The problem says the two mixtures are added together to produce a new mixture totaling 300 grams, so add to the chart:

Protein Other Total
X X

Y Y

X+Y 300

Now add the information about how much protein is in each mixture

Protein Other Total
X .1X X

Y .15Y Y

X+Y 38 300


Now there are two equations with 2 variables:

.1X + .15Y=38
X + Y = 300

Simple method, but it really helps break down harder questions.
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Re: Mixture Problem. Please explain [#permalink] New post 22 Jun 2010, 16:23
can someone explain the logic of the mixture and allegation formula?

the ratio of (difference between the high value and new percentage)
over
(diff b/t high and new) + (diff b/t new and low value)

what does this ratio represent and why, when multiplying the whole to it does it give you the amount in final.....
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Re: Mixture Problem. Please explain [#permalink] New post 23 Sep 2010, 01:13
We know that
1.00x+1.00y=300

and that
0.10x+0.15y=38

so
0.10x+0.15y=38
*10=
1.00x+1.50y=380

Align them under eachother
1.00x+1.50y=380
1.00x+1.00y=300

Means 0.50y=80
80*2=160
y=160
x=300-y
x=300-160
x=140
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Re: Mixture Problem. Please explain [#permalink] New post 24 Sep 2010, 02:21
let x= mixture A ,, then 300-x is Mixture B

.0.1 x + (300-x)0.15=38

after the solving the equation ,,x=140
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Re: Mixture Problem. Please explain [#permalink] New post 29 Sep 2010, 12:53
cool thanks for that 2 equations is the best way for sure
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Re: Mixture Problem. Please explain [#permalink] New post 29 Sep 2010, 12:57
sorry for all those replies my submit button wasnt working properly and it kept not submitting... but obviously it did
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Re: Mixture Problem. Please explain [#permalink] New post 11 Mar 2011, 04:15
This problem is relatively easy once you break it up the way it's supposed to be broken up...

they basically say X lbs +Y lbs = 300 lbs

Now, equate the protein levels together:

0.10 X + 0.15 Y = 38

Solve
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Re: A rabbit on a controlled diet is fed daily 300 grams of a [#permalink] New post 07 Nov 2011, 02:47
just calculation:

0.1*X+0.15*(300-X)=38
X=140
Re: A rabbit on a controlled diet is fed daily 300 grams of a   [#permalink] 07 Nov 2011, 02:47
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