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Re: DS: Coordinate Plane [#permalink]
02 Dec 2010, 12:27
2
This post received KUDOS
Expert's post
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JenniferClopton wrote:
A rectangle is plotted on the standard coordinate plane, with vertices at the origin and (12,0). What are the coordinates of the other two vertices?
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.
So we have two vertices O(0,0) and B(12,0). First note that OA may be either one of the sides or a diagonal.
(1) The length of the diagonal is 13 units --> clearly OA is not a diagonal, so it's one of the sides. Now, if we take the length of the other side to be equal to x then we'll have x^2+12^2=13^2 --> x=5. But from this we can not get the coordinates of the other vertices. As you correctly noted rectangle can be in I quadrant with the other two vertices at (0, 5) and (12, 5) OR in IV quadrant with the other two vertices at (0, -5) and (12, -5). Not sufficient.
(2) The distance between the origin and one of the other vertices is 5 units. Clearly insufficient.
(1)+(2) Still two answers are possible: (0, 5) and (12, 5) OR (0, -5) and (12, -5). Not sufficient.
Re: DS: Coordinate Plane [#permalink]
03 Dec 2010, 04:02
JenniferClopton wrote:
A rectangle is plotted on the standard coordinate plane, with vertices at the origin and (12,0). What are the coordinates of the other two vertices?
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.
The answr must be "E". Not "A". Please post the correct OA.
Here is the simle explanation.
Just imagine the rectangle in the co-ordinate place. You get the answer. No need to use any calculations/values.
The below shows the picture with two rectangles, one in red and another in green, which can be drawn for statement given and which have different co-ordinates except the two given in the question.
Re: DS: Coordinate Plane [#permalink]
03 Dec 2010, 07:59
even if it is implied the answer shud be D not A becoz 5 cant be the diagonal as one side is already 12 and the diagonal will be greater than both sides.
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Jul 2014, 05:44
Bunuel wrote:
JenniferClopton wrote:
A rectangle is plotted on the standard coordinate plane, with vertices at the origin and (12,0). What are the coordinates of the other two vertices?
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.
So we have two vertices O(0,0) and B(12,0). First note that OA may be either one of the sides or a diagonal.
(1) The length of the diagonal is 13 units --> clearly OA is not a diagonal, so it's one of the sides. Now, if we take the length of the other side to be equal to x then we'll have x^2+12^2=13^2 --> x=5. But from this we can not get the coordinates of the other vertices. As you correctly noted rectangle can be in I quadrant with the other two vertices at (0, 5) and (12, 5) OR in IV quadrant with the other two vertices at (0, -5) and (12, -5). Not sufficient.
(2) The distance between the origin and one of the other vertices is 5 units. Clearly insufficient.
(1)+(2) Still two answers are possible: (0, 5) and (12, 5) OR (0, -5) and (12, -5). Not sufficient.
Answer: E.
How can a rectangle have two unequal parallel sides (12 & 13)?
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Jul 2014, 05:48
Expert's post
hamzakb wrote:
Bunuel wrote:
JenniferClopton wrote:
A rectangle is plotted on the standard coordinate plane, with vertices at the origin and (12,0). What are the coordinates of the other two vertices?
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.
So we have two vertices O(0,0) and B(12,0). First note that OA may be either one of the sides or a diagonal.
(1) The length of the diagonal is 13 units --> clearly OA is not a diagonal, so it's one of the sides. Now, if we take the length of the other side to be equal to x then we'll have x^2+12^2=13^2 --> x=5. But from this we can not get the coordinates of the other vertices. As you correctly noted rectangle can be in I quadrant with the other two vertices at (0, 5) and (12, 5) OR in IV quadrant with the other two vertices at (0, -5) and (12, -5). Not sufficient.
(2) The distance between the origin and one of the other vertices is 5 units. Clearly insufficient.
(1)+(2) Still two answers are possible: (0, 5) and (12, 5) OR (0, -5) and (12, -5). Not sufficient.
Answer: E.
How can a rectangle have two unequal parallel sides (12 & 13)?
beats me
It cannot. Where in my solution is written this? _________________
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Jul 2014, 06:05
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.[/quote]
So we have two vertices O(0,0) and B(12,0). First note that OA may be either one of the sides or a diagonal.
(1) The length of the diagonal is 13 units --> clearly OA is not a diagonal, so it's one of the sides. Now, if we take the length of the other side to be equal to x then we'll have x^2+12^2=13^2 --> x=5. But from this we can not get the coordinates of the other vertices. As you correctly noted rectangle can be in I quadrant with the other two vertices at (0, 5) and (12, 5) OR in IV quadrant with the other two vertices at (0, -5) and (12, -5). Not sufficient.
(2) The distance between the origin and one of the other vertices is 5 units. Clearly insufficient.
(1)+(2) Still two answers are possible: (0, 5) and (12, 5) OR (0, -5) and (12, -5). Not sufficient.
Answer: E.[/quote][/quote]
You say clearly OA is not a diagonal, it is one of the side. I think you are mentioning to two sets of parallel lines having length 12 & 13?
Also, how can 13 not be a diagonal, given that it has been explicitly mentioned in the question that it IS a diagonal.
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Jul 2014, 06:31
Expert's post
hamzakb wrote:
You say clearly OA is not a diagonal, it is one of the side. I think you are mentioning to two sets of parallel lines having length 12 & 13?
Also, how can 13 not be a diagonal, given that it has been explicitly mentioned in the question that it IS a diagonal.
You are not reading the question and the solution carefully. Also, with geometry and coordinate geometry question it's always a good idea to make a sketch:
Attachment:
Untitled.png [ 8.01 KiB | Viewed 1341 times ]
OA is NOT the diagonal it's one of the sides, diagonal = 13. Two possible rectangles.
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Jul 2014, 07:27
Bunuel wrote:
hamzakb wrote:
You say clearly OA is not a diagonal, it is one of the side. I think you are mentioning to two sets of parallel lines having length 12 & 13?
Also, how can 13 not be a diagonal, given that it has been explicitly mentioned in the question that it IS a diagonal.
You are not reading the question and the solution carefully. Also, with geometry and coordinate geometry question it's always a good idea to make a sketch:
Attachment:
Untitled.png
OA is NOT the diagonal it's one of the sides, diagonal = 13. Two possible rectangles.
Hope it's clear now.
I get it. I didn't understand properly before.
Thanks a lot!! Your posts are the most helpful I've found on the net
Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
20 Oct 2015, 04:59
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Re: A rectangle is plotted on the standard coordinate plane, [#permalink]
22 Oct 2015, 12:27
Expert's post
1
This post was BOOKMARKED
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
A rectangle is plotted on the standard coordinate plane, with vertices at the origin and (12,0). What are the coordinates of the other two vertices?
(1) The length of the diagonal is 13 units.
(2) The distance between the origin and one of the other vertices is 5 units.
There is one variable (b), and 2 equations are given; the answer is likely to be (D). From condition 1, b=5, -5. So this is an insufficient condition as it does not give a unique answer. condition 2, similarly, gives b=5, -5, so this is also insufficient for the same reason. Even if we combine the 2 conditions, b=5,-5, so as a whole, they are insufficient, so the answer is going to be (E).
For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E. _________________
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