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# A rectangular box is 10 inches wide, 10 inches long, and 5

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Intern
Joined: 16 Apr 2005
Posts: 15
Followers: 0

Kudos [?]: 0 [0], given: 0

A rectangular box is 10 inches wide, 10 inches long, and 5 [#permalink]  20 Apr 2005, 10:32
A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box?

1) 15
2) 20
3) 25
4) 10 * square root 2
5) 10 * square root 3

Is there an equation to figure this out?
Director
Joined: 27 Dec 2004
Posts: 908
Followers: 1

Kudos [?]: 17 [0], given: 0

Ans is A

Diagonal is the longest distance in a rectangular box.

Diagonal D = sqrt (L^2 + W^2 + H^2)

D = sqrt (10^2 + 10^2 + 5^2)
D = sqrt (225)
D = 15.
Senior Manager
Joined: 19 Feb 2005
Posts: 488
Location: Milan Italy
Followers: 1

Kudos [?]: 10 [0], given: 0

well, my reasoning below leads me to 15.
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VP
Joined: 25 Nov 2004
Posts: 1495
Followers: 6

Kudos [?]: 38 [0], given: 0

thearch wrote:
well, my reasoning below leads me to 15.

nice and clear drawing
Senior Manager
Joined: 11 May 2004
Posts: 458
Location: New York
Followers: 1

Kudos [?]: 14 [0], given: 0

This is an old post, but I just wanted to make sure everyone knew the quick and easy formula:

Take 10^2+10^2+5^2
We get 100+100+25 = 225
Take the square root of this to get 15.

No geometry or equations needed.
Senior Manager
Joined: 03 Nov 2005
Posts: 397
Location: Chicago, IL
Followers: 3

Kudos [?]: 28 [0], given: 17

The longest rot that can fit into a rectangular box=sq rt. l^2+w^2+h^2= sqrt.10^2+10^2+5^2=sqrt 222=15

A stands
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