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Re: a rectangular piece in cylinder [#permalink]
There are two ways of doig this :

1 in which circumference = 2*pi*r = 12 => r = 6/pi and height = 16 => volume = pi * 36/pi^2 * 16 = 576/pi

2 in which circumference = 2*pi*r = 16 => r = 8/pi and height = 12 => volume = pi * 64/pi^2 * 12 = 768/pi

Answer - B
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Re: a rectangular piece in cylinder [#permalink]
subhashghosh wrote:
There are two ways of doig this :

1 in which circumference = 2*pi*r = 12 => r = 6/pi and height = 16 => volume = pi * 36/pi^2 * 16 = 576/pi

2 in which circumference = 2*pi*r = 16 => r = 8/pi and height = 12 => volume = pi * 64/pi^2 * 12 = 768/pi

Answer - B



the first step is important:

concluding that 12 or 16 are the circumference was based on what premise?
the Q was saying that the measure of the box were 12/16 or am i missing somthing?
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Re: a rectangular piece in cylinder [#permalink]
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It's like this :
When you roll a piece of paper into a cylinder, the length or breadth becomes a circle of the base. Now the perimeter of this circle is equal to the length of the side, and the perimeter of a circle = circumference of a circle. You can try to roll a paper and you'll get the idea.
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Re: a rectangular piece in cylinder [#permalink]
THANK'S. i imagined it quite differently. you treated that like a roll and i treated it as sitting on tha radius. that's great
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Re: a rectangular piece in cylinder [#permalink]
Yup, as I said, trying to do this in real life can give valuable insight into how the 3-D figures look like. Glad to help :)
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Re: a rectangular piece in cylinder [#permalink]
v= pi*r^2*h
use r=6, h = 16 and calculate
use r= 8 and h = 12 and calculate

B...



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