Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A right circular cone is inscribed in a hemisphere so that [#permalink]
09 Jul 2012, 03:41

Expert's post

3

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

15% (low)

Question Stats:

67% (01:50) correct
33% (01:01) wrong based on 289 sessions

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

(A) \sqrt{3}:1

(B) 1:1

(C) \frac{1}{2}:1

(D) \sqrt{2}:1

(E) 2:1

Diagnostic Test Question: 20 Page: 23 Difficulty: 600

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
09 Jul 2012, 03:42

1

This post received KUDOS

Expert's post

SOLUTION

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

(A) \sqrt{3}:1

(B) 1:1

(C) \frac{1}{2}:1

(D) \sqrt{2}:1

(E) 2:1

Note that a hemisphere is just a half of a sphere.

Now, since the cone is a right circular one, then the vertex of the cone must touch the surface of the hemisphere directly above the center of the base (as shown in the diagram below), which makes the height of the cone also the radius of the hemisphere.

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
09 Jul 2012, 05:28

1

This post received KUDOS

Bunuel wrote:

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
13 Jul 2012, 02:11

Expert's post

SOLUTION

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

(A) \sqrt{3}:1

(B) 1:1

(C) \frac{1}{2}:1

(D) \sqrt{2}:1

(E) 2:1

Note that a hemisphere is just a half of a sphere.

Now, since the cone is a right circular one, then the vertex of the cone must touch the surface of the hemisphere directly above the center of the base (as shown in the diagram below), which makes the height of the cone also the radius of the hemisphere.

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
25 Sep 2013, 15:09

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
06 May 2014, 11:57

Bunuel wrote:

SOLUTION

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

(A) \sqrt{3}:1

(B) 1:1

(C) \frac{1}{2}:1

(D) \sqrt{2}:1

(E) 2:1

Note that a hemisphere is just a half of a sphere.

Now, since the cone is a right circular one, then the vertex of the cone must touch the surface of the hemisphere directly above the center of the base (as shown in the diagram below), which makes the height of the cone also the radius of the hemisphere.

Attachment:

Cone.png

Answer: B.

Hi Bunuel, how did you conclude the underlined in above statement? Thanks!

Re: A right circular cone is inscribed in a hemisphere so that [#permalink]
07 May 2014, 03:25

Expert's post

Dienekes wrote:

Bunuel wrote:

SOLUTION

A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere?

(A) \sqrt{3}:1

(B) 1:1

(C) \frac{1}{2}:1

(D) \sqrt{2}:1

(E) 2:1

Note that a hemisphere is just a half of a sphere.

Now, since the cone is a right circular one, then the vertex of the cone must touch the surface of the hemisphere directly above the center of the base (as shown in the diagram below), which makes the height of the cone also the radius of the hemisphere.

Attachment:

The attachment Cone.png is no longer available

Answer: B.

Hi Bunuel, how did you conclude the underlined in above statement? Thanks!

Consider the cross-section. We'd have an isosceles triangle inscribed in a semi-circle:

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...