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# A saleswoman s monthly income has two components, a fixed

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26 Nov 2006, 06:38
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A saleswomanâ€™s monthly income has two components, a fixed component of $1000 per month, and a variable component, which is$C for each set of encyclopaedias that she sells in that month over a sales target of 2 sets. How much did she earn in March?

(1) If she had sold three fewer sets than she actually did, her March income would have been $600 less. (2) If she had sold 8 sets of encyclopaedias, her income in March would have been over$4000

Last edited by kevincan on 26 Nov 2006, 07:27, edited 1 time in total.
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26 Nov 2006, 06:53
kevincan wrote:
A saleswomanâ€™s monthly income has two components, a fixed component of $1000 per month, and a variable component, which is$C for each set of encyclopaedias that she sells in that month over a sales target of 3 sets. How much did she earn in March?

(1) If she had sold three fewer sets than she actually did, her March income would have been $600 less. (2) If she had sold 8 sets of encyclopaedias, her income in March would have been over$4000

I get A here

Let n be the # of copies that she sells

we know that her income is (n-3)*C + 1000 for any given month----(I)

(1) says that If she actually sells 3 copies less than actually she did then
her income is less by \$600

So (n-6)*C + 1000 ------------------(II)

From (I) and (II) we get her March income

From (2) in the given premise

we have 5*C + 1000 > 4000

So C>600

But we cannot tell exactly how much she got ...

So IMO it is A
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26 Nov 2006, 07:12
S1: If sales=4sets,c=600/set
If sales=5, c=300
if sales=6, c=200
Insuff, 'cause we can't assume how many sets were sold

S2:c>600
Insuff

Together, If s2 says c=600, then ans is c. But, c>600. How could that be? Where am I going wrong?
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26 Nov 2006, 07:37
We need the no. of sets sold.

S1: c could be 200, 300, 600
insuff
S2:c>500
insuff
together - 1set - suff
My ans:C
26 Nov 2006, 07:37
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