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A saleswoman's monthly income has two components, a fixed

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Joined: 21 Jul 2006
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A saleswoman's monthly income has two components, a fixed [#permalink] New post 17 Jul 2008, 22:46
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A saleswoman's monthly income has two components, a fixed component of $1000 per month, and a variable component, which is $C for each set of encyclopedias that she sells in that month over a sales target of n sets, where n > 1. How much did she warn in March?

(1) If she had sold three fewer sets than she actually did, her March income would have been $600 less.

(2) If she had sold 8 sets of encyclopedias, her income in March would have been over $400




Explain your answer please.
thanks
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Re: DS: Equations [#permalink] New post 17 Jul 2008, 23:34
tarek99 wrote:
A saleswoman's monthly income has two components, a fixed component of $1000 per month, and a variable component, which is $C for each set of encyclopedias that she sells in that month over a sales target of n sets, where n > 1. How much did she warn in March?

(1) If she had sold three fewer sets than she actually did, her March income would have been $600 less.

(2) If she had sold 8 sets of encyclopedias, her income in March would have been over $400

Explain your answer please.
thanks


E for me

Let A be her total income in March
Let X be the total number of encyclopedias she sold in March

then we have

1000 + (X-N)C = A....(1)

1) 1000 + (X-3-N)C = A - 600

subtracting this eqn from above (1) we can get the value of C.

But still we don't know the value of X

2) insuff alone. (we don't know value of C)
(I didn't understand this sentence, as her fixed component of earning is >1000$
what is meant by over 400$?)

Together insuff as well.
Re: DS: Equations   [#permalink] 17 Jul 2008, 23:34
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