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# A sample of x litres from a container having a 60 litre

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A sample of x litres from a container having a 60 litre [#permalink]

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03 Jul 2004, 21:04
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal proportions. What is the value of x?

(1) 6 litres (2) 10 litres
(3) 30 litres (4) None of these
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I'm crossing the bridge.........

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03 Jul 2004, 23:14
I went for substition.

60

24 36 (2:3)

Chk ans: 10

4 6 (2:3)

Since 10 is removed ==> Remaining is (24-4 = 20 Milk and 36-6=30 Water)

Add 10 lit of pure milk = 30 Milk and 30 water = 60

Ans : 10
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04 Jul 2004, 05:00
ashkg wrote:
A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal proportions. What is the value of x?

(1) 6 litres (2) 10 litres
(3) 30 litres (4) None of these

Container = 60 litres
Milk left after x litres were taken = 2/5*(60-x)
x litres of milk were added later
the proportion of milk to water in the resulting mixture was 1/2 to 1/2
therefore, 30 litres of milk were in the resulting mixture

=> 2/5*(60-x) +x = 30
=> x=10.
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04 Jul 2004, 05:59
Easier still:

quantity of milk (finally) = 30 lit.
quantity of water (finally) = 30 lit.

Initial qualtity of milk = 24
Initial qualtity of water = 36

meaning 6 lit. of warer has been removed => 4 lit of milk has been removed. Therefore a total of 10 lit.of the solution has been removed!!
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