A scientist is studying bacteria whose cell population doubles at constant intervals, at which times each cell in the population divides simultaneously. Four hours from now, immediately after the population doubles, the scientist will destroy the entire sample. How many cells will the population contain when the bacteria is destroyed?
(1) Since the population divided two hours ago, the population has quadrupled, increasing by 3,750 cells.
(2) The population will double to 40,000 cells with one hour remaining until the scientist destroys the sample.
1) we know that the population is now 3750 + x and we know the growth interval. we just need the val of x. ins.
2) ins. we need the interval to determine the exact amt. of cells in 4 hrs. this only tells us that there will be 40K cells in 3 hrs.
1&2 tells us that the population quadruples every 2 hrs. we can use this along with stmnt. 2 to solve. I get C.