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# A set contains three numbers. The average (arithmetic mean)

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Joined: 30 Aug 2003
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A set contains three numbers. The average (arithmetic mean) [#permalink]

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30 Dec 2003, 10:02
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A set contains three numbers. The average (arithmetic mean) of the two smallest numbers in the set is 5 less than the average of all three numbers in the set. If the greatest number in the set is 5, what is the sum of the two smallest numbers in the set?

A: 5
B: 10
C: -10
D: -20
E: 20
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shubhangi

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30 Dec 2003, 10:54
is it D?

might be a quicker way but this is how i did it.

#1 - a
#2 - b
#3 - 5

just solve:

(a+b+5)/3 - (a+b)/2 = 5
SVP
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10 Jan 2004, 22:08
got the same

(a+b)/2 = (a+b+c)/3 - 5

(a+b)( 1/2-1/3) = 5/3-5 = -10/3

a+b = -16 * 6 /2 = -20
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