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A set of numbers has the property that for any number t in

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New post 01 Dec 2005, 13:28
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1
is in the set, which of the following must also be in the set?
I. -3
II. 1
III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
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New post 01 Dec 2005, 14:23
D.

search in the archive. you will get discussion on this.
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New post 01 Dec 2005, 18:20
-1 must have t+2 = 1
So if 1 is in the set, 3 must be in it, and 5 must be in it.

So Ans: D
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New post 01 Dec 2005, 21:32
ywilfred wrote:
-1 must have t+2 = 1
So if 1 is in the set, 3 must be in it, and 5 must be in it.

So Ans: D


Why not apply the same logic to -3 + 2 = -1?

The problem does not specify that (t) begins from -1, does it?
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New post 02 Dec 2005, 11:00
OA is D. It is disputable that -3 is in the set and every disputable answers is wrong on the GMAT.
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New post 02 Dec 2005, 15:10
The stem would have to state "for any number t, t-2 is in the set" for -3 to be necessarily included (or for every number t+2, t is in the set maybe). It's kind of a chicken/egg debate but I read it and didn't think -3 had to be included.

-3 does not have to be there for -1 to be in the set.
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