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A set of numbers has the property that for any number t in

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New post 30 Dec 2005, 00:38
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A
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D
E

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A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?
I. -3
II. 1
III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III

Im confused!!
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JAI HIND!

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New post 30 Dec 2005, 04:55
E

If -1 is in the set, then -1+2=1 is in the set, if 1 then 3, if 3 then 5.

If t+2=-1 is in the set than -3 is also in.

Hope this helps
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New post 30 Dec 2005, 22:49
allabout wrote:
E. If -1 is in the set, then -1+2=1 is in the set, if 1 then 3, if 3 then 5.
If t+2=-1 is in the set than -3 is also in.
Hope this helps


-1 = t not t+2. so (i) is not possible. therefore D is correct....
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New post 31 Dec 2005, 05:14
'E' is correct!

all numbers 1, -3 & 5 should be there...

1) If t=-1 then t+2 = 1 & t+4 = 5

2) If t+2 = 1 then t = -3

Such number line approach is useful

t---------t+2----------t+4----------t+6 ..
(-1)-------1-------------3------------5
(-3)------(-1)-----------1------------3
(-5)------(-3)----------(-1)----------1
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New post 31 Dec 2005, 14:57
I would go with D.
Given "t in the set => t+2 in the set". Converse may not be true.

mmegps
  [#permalink] 31 Dec 2005, 14:57
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