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A set of numbers has the property that for any number t in [#permalink]
15 Jul 2006, 19:06

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0% (00:00) wrong based on 0 sessions

A set of numbers has the property that for any number t in the set, t + 2 is in the set. If â€“1 is in the set, which of the following must also be in the set?

I. -3
II. 1
III. 5

A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III

I got this one wrong because I assumed something... I am not sure if I was supposed to assume it or not... Please explain

If -1 is in set, then 1 must be in the set If 1 is in the set, then 3 must be in the set if 3 is in the set, then 5 must be in the set

The question does not say that t-2 has to be in the set - only t+2. So (I) may, or may not be true.

I do not understand why 1 cannot be in the set. After all ,when you say that t-2 cannot be in the set, then even 3 shouldnt be there in the set because 5-2=3= (t-2). I think it definitely can.

-1 is in the set, 1 must be in the set. And if 1 is in the set, 3 must be in and 5 must be in. -3 is subjective as -1 could be the first element of the set.