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# A set of numbers has the property that for any number t in

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A set of numbers has the property that for any number t in [#permalink]

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17 Oct 2008, 07:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?

I. -3
II. 1
III. 5

A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
VP
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18 Oct 2008, 22:41
chenhong1224 wrote:
A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?

I. -3
II. 1
III. 5

A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III

If -1 is in the set then 1 (-1+2) should also be in the set. So 1 must be in the set.

now if t=-3 then t+2 = -1. -3 can be in the set, but we are not sure. -1 could be the first number in the set.

Is it B ??
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VP
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18 Oct 2008, 22:52
chenhong1224 wrote:
A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?

I. -3
II. 1
III. 5

A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III

IMO D

t=-1 => -1+2=1 is in the set
if 1 is in the set then 1+2 =3 has to be in the set
Hence this goes on neitherstart and end points are mentioned we are not sur of initial element ,t+1 must exist makes it necessary for all the elements to exist
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Re: set   [#permalink] 18 Oct 2008, 22:52
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