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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7}

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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink] New post 23 Jan 2011, 10:31
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Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:- 1/2
(Sorry I don't have the answer choices for the question above.)
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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} [#permalink] New post 23 Jan 2011, 10:48
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MichelleSavina wrote:
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:- 1/2
(Sorry I don't have the answer choices for the question above.)


Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.
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Re: A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7}   [#permalink] 23 Jan 2011, 10:48
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7}

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