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# A shade of paint is made by evenly mixing m gallons of white

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A shade of paint is made by evenly mixing m gallons of white [#permalink]  24 Nov 2007, 02:15
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60% (01:43) correct 39% (00:20) wrong based on 2 sessions
A shade of paint is made by evenly mixing m gallons of white paint, costing \$12 a gallon, with n gallons of blue paint, costing \$30. What is the cost, in dollars per gallon, of the resulting mixture?

12m +30n
42(12m +30n)
(12m +30n) / 42
(12m +30n) / (M+ N)
42(M+ N) / (12m +30n)

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Re: mixtures - variables [#permalink]  13 Aug 2009, 05:48
M gallons of white paint and N gallons of blue paint are combined to form a new mixture. The total number of gallons in the new mixture will be M + N gallons

M gallons of white paint cost \$12, so the cost of adding this mixture is 12M
N gallons of blue paint cost \$30, so the cost of adding this mixture is 30N

The cost per gallon of the new mixture is equal to the total cost of all the paint used divided by the total number of gallons used to produce it:

cost of new mixture: 12M + 30N
total gallons used: M+N

cost per gallon = total cost/total gallons used = (12M + 30N)/(M+N)

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Re: mixtures - variables [#permalink]  05 Sep 2009, 13:06
Hi everyone, I got confused when the problem said "costing \$30", didn't realized that it implied \$30/gallon. Anyways no other answer choices work otherwise suggesting that the above answers is highly likely.
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Re: mixtures - variables [#permalink]  09 Oct 2009, 12:44
formula for finding mean price of the mixture:

Cm= CaQa+CbQb/Qa+Qb

where

Ca= cost of A
Cb= cost of B
Qa=quantity of A
Qb=Quantity of B

use this formula to find the unit price /mean price of the mix
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Re: mixtures - variables [#permalink]  10 Oct 2009, 10:07
I will go with ans (12*m + 30*n)/(m+n)
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Re: mixtures - variables [#permalink]  26 Jun 2011, 17:45
Basically have to figure out the average...

D it is...
Re: mixtures - variables   [#permalink] 26 Jun 2011, 17:45
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