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A small company employs 3 men and 5 women. If a team of 4

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A small company employs 3 men and 5 women. If a team of 4 [#permalink] New post 11 Aug 2007, 05:04
A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
1/14
1/7
2/7
3/7
1/2

Why isn't it straight 5C2/8C4??
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Re: Probability [#permalink] New post 11 Aug 2007, 08:50
gkslko101 wrote:
A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
1/14
1/7
2/7
3/7
1/2

Why isn't it straight 5C2/8C4??


I get D (3/7) for this.

You have not considered the ways to select the 2 men in the group. So the probability should be (5C2/8C4) * 3C2.
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Re: Probability [#permalink] New post 11 Aug 2007, 23:33
gkslko101 wrote:
A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
1/14
1/7
2/7
3/7
1/2

Why isn't it straight 5C2/8C4??


i get 3/7

probability = M*W / total

M (2 men): 3C2 = 3
W (2 women): 5C2 = 10
total = 8C4 = 70

(3*10) / 70 = 30/70 = 3/7
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 [#permalink] New post 13 Aug 2007, 03:21
Can someone explain the setup a little more please... The math looks good, but can you elaborate on how you set up the equations.
  [#permalink] 13 Aug 2007, 03:21
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