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A small, rectangular park has a perimeter of 560 feet and a

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A small, rectangular park has a perimeter of 560 feet and a [#permalink] New post 27 Sep 2008, 13:05
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A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 200 feet.
What is its area, in square feet?
A. 19,200
B. 19,600
C. 20,000
D. 20,400
E. 20,800
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Re: PS: Area [#permalink] New post 27 Sep 2008, 13:45
arorag wrote:
A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 200 feet.
What is its area, in square feet?
A. 19,200
B. 19,600
C. 20,000
D. 20,400
E. 20,800



2 (l+w) = 560 means l+w = 280

Sqrt ( l^2 + w^2) = 200 means (l2^+w^2) = 40000

square both sides of (l+w) =280

l^2 + w^2 +2lw = 78400

means 2lw= 38400 lw=19,200

Hence A
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Re: PS: Area [#permalink] New post 27 Sep 2008, 13:45
A:

I thought the 200 as the hypotenuse was a little 'fishy', so I started thinking of it as a 3-4-5 triangle: 200 as the hypotenuse, 120 and 160 as the legs and it worked: 120*160 = 19,200.
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Re: PS: Area [#permalink] New post 27 Sep 2008, 14:08
same here:

a+b = 280

(a+b)(a+b) =78'400

a^2+2ab+b^2 = 78'400

a^2+b^2 = 200^2 = 40'000

2ab = 38'400

ab = 19'200
Re: PS: Area   [#permalink] 27 Sep 2008, 14:08
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