A small water pump would take 2 hours to fill an empty tank

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A small water pump would take 2 hours to fill an empty tank [#permalink]

07 Feb 2012, 07:00

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Can someone assist me with solving this question?

A small water pump would take 2 hours to fill an empty tank. A larger pump would take 1/2 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time?

A) 1/4
B) 1/3
C) 2/5
D) 5/4
E) 3/2

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Re: Quant PS [#permalink]

07 Feb 2012, 07:09

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domu904 wrote:

Rate of the small pump is 1/2 tank/hour (rate is reciprocal of time);
Rate of the larger pump is 2 tank/hour;

Combined rate of the two pumps is 1/2+2=5/2 tank/hour, hence together they will fill the empty tank in 1/(5/2)=2/5 hours (time=job/rate).

Answer: C.

Theory on work/rate problems:
two-consultants-can-type-up-a-report-126155.html?hilit=know%20rate%20work%20reciprocal#p1030079
work-word-problems-made-easy-87357.html

Hope it helps.

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Re: Quant PS [#permalink] 07 Feb 2012, 07:09

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A small water pump would take 2 hours to fill an empty tank

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A small water pump would take 2 hours to fill an empty tank

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