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A spirit and water solution is sold in a market. The cost pe [#permalink]

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17 Mar 2014, 23:01

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A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?

Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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18 Mar 2014, 00:21

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It is given that the cost is directly proportional to the fraction of the spirit in volume. 50% spirit corresponds to 50 cents So 33.33% spirit will correspond to 33.33 cents

Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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18 Mar 2014, 23:22

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qlx wrote:

The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has

This statment can also be re-stated as "The Cost of 1 litre of Spririt is 50 Cents and water is free".

If the mixture is changed by adding another litre of water, still the amount of Spirit in the solution is unchanged and you have pay only for the spirit.

Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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02 Apr 2014, 13:06

qlx wrote:

A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?

A. 13 B. 33 C. 50 D. 51 E. 52

I solved it as :

Cost = k (Part of spirit)

50cents = k (1/2) -------(1) k=100

Now part (fraction of spirit in 3 Liters) 1/3

Cost=100(1/3) = 33.33 ----- (B)

I am not sure what is wrong with my understanding...

1L spirit + 1L water = 50% concentration 1L spirit + 2L water = 33.33% concentration

Logically price should be less for diluted liquid as in 1L solution spirit has reduced in parts per liter.
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A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?

A. 13 B. 33 C. 50 D. 51 E. 52

I solved it as :

Cost = k (Part of spirit)

50cents = k (1/2) -------(1) k=100

Now part (fraction of spirit in 3 Liters) 1/3

Cost=100(1/3) = 33.33 ----- (B)

I am not sure what is wrong with my understanding...

1L spirit + 1L water = 50% concentration 1L spirit + 2L water = 33.33% concentration

Logically price should be less for diluted liquid as in 1L solution spirit has reduced in parts per liter.

You missed the following part: The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has.

According to the above the cost of each liter of the solution = \(k*\frac{s}{s+w}\). So, s+w liters of the solution should cost \(k*\frac{s}{s+w}*(s+w)=ks\). So, we can see that the price of the solution is based only the amount of the spirit there (s), which means that both solutions must have the same price because both have 1 liter of spirit.

Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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03 Apr 2014, 04:09

Thanks Bunuel, I got it now.. I think I was sleeping while reading this question
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Piyush K ----------------------- Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison Don't forget to press--> Kudos My Articles: 1. WOULD: when to use?| 2. All GMATPrep RCs (New) Tip: Before exam a week earlier don't forget to exhaust all gmatprep problems specially for "sentence correction".

Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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19 Apr 2014, 03:30

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Another Approach, a more mathematical one:

Cost/Ltr @ Concentration

Consider a constant of proportionality as K.

So,

Cost/Ltr = K * Conc.

Scenario 1:

50/2 = K * 1/2 => K=50

Scenario 2:

C/3 = K * 1/3

=> C=K

=>C=50
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Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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26 Jan 2015, 21:26

qlx wrote:

A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?

A. 13 B. 33 C. 50 D. 51 E. 52

'Tis a tricky question. I had to reread it twice to notice it said "cost per liter of the solution is directly proportional to the part of spirit." That means the cost is still the same since there is 1 liter in both instances.

A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?

A. 13 B. 33 C. 50 D. 51 E. 52

'Tis a tricky question. I had to reread it twice to notice it said "cost per liter of the solution is directly proportional to the part of spirit." That means the cost is still the same since there is 1 liter in both instances.

C. 50 cents

Yes, ensure that you understand the relation thoroughly!

Cost per liter = K * Fraction of Spirit

50 cents is the cost of 2 liters of solution (1 part water, 1 part spirit). So cost per liter is 25 cents. Fraction of spirit is 1/2.

25 = K * (1/2) K = 50

Cost per liter = 50 * (1/3) (1 part spirit, 2 parts water) Cost for 3 liters = 50 * (1/3) * 3 = 50 cents
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Re: A spirit and water solution is sold in a market. The cost pe [#permalink]

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