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A store currently charges the same price for each towel that [#permalink] New post 15 Jun 2006, 17:36
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A store currently charges the same price for each towel that it sells. If the current price of each towel were to be increased by $1, 10 fewer of the towels could be bought for $120, excluding sales tax. What is the current price of each towel?

A) 1
B) 2
C) 3
D) 4
E) 12
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 [#permalink] New post 15 Jun 2006, 17:45
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C) 3

Given pxq =120 .... (a)

Also (p+1) x (q-10) = 120

i.e. q = 10(1+p)

Replacing q in (a)
p^2+p = 12

or (p+4)(p-3) = 0

i.e p=-4 or 3.
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Re: From Old PowerPrep... [#permalink] New post 15 Jun 2006, 17:50
chiragr wrote:
A store currently charges the same price for each towel that it sells. If the current price of each towel were to be increased by $1, 10 fewer of the towels could be bought for $120, excluding sales tax. What is the current price of each towel?

A) 1
B) 2
C) 3
D) 4
E) 12



Let current price be x
towels that can be bought with $120 = 120/x

If price is x+1, towels bought = 120/(x+1) = (120/x) - 10
Solving for x yields x=3

Hence C
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 [#permalink] New post 15 Jun 2006, 18:13
Original price = $x

# of towels bought with $120 = 120/x

New price = $(x+1)

# of towels bought with 120 = 120/(x+1) = 120/x - 10
120/(x+1) = (120 - 10x)/x
120x = 120-10x(x+1)
120x = 120x + 120 - 10x^2 -10x
x^2 - x - 12 = 0
(x+4)(x-3) = 0

x = 3


Current price = 3
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 [#permalink] New post 16 Jun 2006, 01:34
What I did was took numbers and started calculating.......

Equation can be written but since the numbers were small calculating ws easier.

120/3 = 40

New price = 3 + 1 = 4

Number = 120/4 = 30

30 is ten fewer than 40 hence

3 is the intial price
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 [#permalink] New post 16 Jun 2006, 07:32
jaynayak wrote:
What I did was took numbers and started calculating.......

Equation can be written but since the numbers were small calculating ws easier.

120/3 = 40

New price = 3 + 1 = 4

Number = 120/4 = 30

30 is ten fewer than 40 hence

3 is the intial price


My thoughts exactly. I calculated the formula:

120/P = 10+ 120/(P+1) then I started pluggin in numbers since it looked much easier to do then to solve this algebraically.
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 [#permalink] New post 16 Jun 2006, 12:37
"If the current price of each towel were to be increased by $1, 10 fewer of the towels could be bought for $120, excluding sales tax"

Doesn't this mean...

Original N towel, total price X and price of towel is X/N
New N-10 towel, total price 120 and price of towel is X/N+1

How do I conclude that original price X is $120?

If this were to be DS problem I would say that I can not solve this problem with available information.

Any one agrees or I suck in verbal!
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 [#permalink] New post 16 Jun 2006, 13:21
Current:
Price = p
Can be purchased in $120 = 10
So p*n = 120..........Eq1

After increasing price we have (p+1) (n-10) = 120.........Eq2

Solving Eq1 and Eq2 we get p = 3
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Total price [#permalink] New post 26 Aug 2006, 21:32
Chiragr,

120 is not the total price X, it is the amount with which someone can buy n number of towels.

I thought the problem clearly states that... its not to look at the problem so literally I guess :)

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Try this link.. [#permalink] New post 06 Jun 2007, 20:24
http://www.gmatclub.com/phpbb/viewtopic ... ght=towels

I just did a search for towel because I remember seeing this problem before.



For a problem like this you could always start with the answer choices and work backwards if the formula just isn't coming to you.
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 [#permalink] New post 06 Jun 2007, 23:51
C

Let P = price per towel

You can figure that 120/P = the quantity of towels sold.

add 1 to P (price) and you have P+1, which equals the new price per towel.

The new price per towel, P+1, results in 10 fewer towels being purchased for $120. The equation below reflects this:

120/P+1 = 120/P - 10

Now, solve for P.
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Re: Number Properties Question 2 [#permalink] New post 07 Jun 2007, 00:12
700dreamer wrote:
A store currently charges the same price for each towel that it sells. If the current price of each towel were to be increased by $1, 10 fewer of the towels could be bought for $120, excluding tax. What is the current price of each towel?

A) $1
B) $2
C) $3
D) $4
E) $12


Current price of each towel = $x

Number of current towels which can be bought for $120 is equal to (120/x)

Increased current price = $x + $1

[(120/x)-(10)]*(x+1) = 120

becomes a quadratic equation : x^2 + x-12 = 0

(x+4)(x-3) = 0

thus x=3

C is the answer.
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PS [#permalink] New post 11 Jul 2007, 16:04
HELP ME.

A store currently charge the same price of a towel that it sells.If the current price is to be increased by $1. 10 fewer of the towels could be bought for $120. What is the current price?
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 [#permalink] New post 11 Jul 2007, 21:33
It's kinda hard to know exactly what the question is asking bc you have some grammatical errors...can you re-state the question exactly how it is written in the text/program?
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 [#permalink] New post 12 Jul 2007, 10:50
I thought the answer was 3, because i picked a low number and figured it out.
Would you mind showing how you set up your equation, sonfbm?
Thanks
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 [#permalink] New post 12 Jul 2007, 11:11
simonsanchez wrote:
I thought the answer was 3, because i picked a low number and figured it out.
Would you mind showing how you set up your equation, sonfbm?
Thanks


If the current price is x, then

120/x = 120/(x+1) + 10
x = 3.
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Re: 200. current price [#permalink] New post 23 Feb 2008, 20:37
i get C, 3 dollars.

let old price = x, therefore new price is x+1

amount of towels you could buy with old price is 120/x, and amount with new price is (120/x+1)-10

set these equations equal to each other, and solve for x. youll end up with a quadratic with roots -4 and 3. -4 is inadmissable, so 3 is your answer.

try it out: for 120 dollars, you can get 40 towels at 3 bucks a pop. Now, for a dollar increase, i.e. 4 dollars, you can get only 30 towels. Thats a difference of 10 towels due to a $1 increase in price.
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Re: OG - PS 200 [#permalink] New post 02 Mar 2008, 09:37
C

Here is what I have done...

Assuming n-no of towels, x-unit price of towel before increase:

n*x=120
(n-10)*(x+1)=120

You could solve the equations, but I tried different values of n ending with 0 from 120's prime factors - 5*3*2*2*2
so n could be 20, 30, 40 and corresponding x values are 6,4 and 3. And 40 and 3 satyisfy the second condition, so 3 is the answer.
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Re: What is the most efficient way to solve this problem- Ideas? [#permalink] New post 22 Jun 2008, 08:58
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this question is actually very simple and can be best approached by trying numbers..

so suppose orig.price=3..then 120/3=40 towels
increase it by 1=new price=4 120/4=30 towels..


another hint that you want to look for is that 120..what ever numbers you look for must be factors of 120..

in our case that doesnt help since all of them are factors of 120.
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Algebra Applied [#permalink] New post 16 Sep 2010, 07:09
OG 195. A store currently charges the same price for each
towel that it sells. If the current price of each towel
were to be increased by $1, 10 fewer of the towels
could be bought for $120, excluding sales tax. What is
the current price of each towel?
(A) $ 1
(B) $ 2
(C) $ 3
(D) $ 4
(E) $ 12

Suggest shortest way to solve the problem.
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Algebra Applied   [#permalink] 16 Sep 2010, 07:09
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