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# A student must choose exactly two out of three electives:

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SVP
Joined: 16 Oct 2003
Posts: 1815
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A student must choose exactly two out of three electives: [#permalink]  04 Nov 2003, 12:38
A student must choose exactly two out of three electives: art, French, and
mathematics. He chooses art with probability 5/8, French with probability
5/8, and art and French together with probability 1/4. What is the probability that he chooses mathematics? What is the probability that he chooses either art or French?
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 8 [0], given: 0

What is the probability that he chooses mathematics? 3/4?

What is the probability that he chooses either art or French? 1.
Do you mean "what is the probability he chooses art or French but not both art and French? Because that is 3/4.

I think...
SVP
Joined: 16 Oct 2003
Posts: 1815
Followers: 4

Kudos [?]: 48 [0], given: 0

My answer is p(Maths) = 1/4
and p(art) or p(French) = 3/4
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 8 [0], given: 0

if the student has to take two of the three classes, he must take either french or math.
He must take either math or art.
He must take either french or art.

Give me an example of a student who takes the two classes that he is required to have taken, without taking art or french!
SVP
Joined: 03 Feb 2003
Posts: 1611
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Kudos [?]: 74 [0], given: 0

P(A)=5/8
P(F)=5/8
P (A and F)=1/4

He chooses exactly two!!!

In this case P(M)=P(A and M)+P(F and M)
and P(A or F) = P(A and M)+P(F and M)

I think the questions have the same answers.

P(A and M)+P(F and M)+P(A and F) = 1 (a complete pack of probability)
P(A and M)+P(F and M)+1/4=1
P(A and M)+P(F and M)=3/4

3/4 for both questions
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