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# A system of equations

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Intern
Joined: 08 Nov 2011
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A system of equations [#permalink]

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30 Dec 2011, 18:31
Question: Manhattan GMAT says "can't solve -- these are the same equations":

50x+20y=15
10x+4y=3

However, if you substitute the following into either one of equations:

x=3/10 and y=0

you can solve the system of these equations...
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Joined: 04 Sep 2011
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WE: Architecture (Investment Banking)
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Re: A system of equations [#permalink]

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30 Dec 2011, 21:26
This is because the 1st equation can be obtained by multiplying the second equation with 5. Therefore you can have all the possible combinations for x,y which falls on the line 10x+4y =3
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Re: A system of equations [#permalink]

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30 Dec 2011, 22:30
Well, can we say than that there are multiple solutions to that system of equations instead of "no solution" per GMAT? I understand that there is a multitude of possible combinations of X and Y....
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Re: A system of equations [#permalink]

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31 Dec 2011, 07:37
Yes denisjax you can have multiple solutions. Read the second line of my previous answer.
Re: A system of equations   [#permalink] 31 Dec 2011, 07:37
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# A system of equations

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