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A taxi company charges f cents for the first mile of the [#permalink]
01 Oct 2012, 04:22

Expert's post

3

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

81% (02:03) correct
19% (01:09) wrong based on 366 sessions

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

(1) The company charges $0.90 for a 2-mile ride. (2) The company charges $1.20 for a 4-mile ride.

Practice Questions Question: 54 Page: 279 Difficulty: 600

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

(1) The company charges $0.90 for a 2-mile ride. (2) The company charges $l.20 for a 4-mile ride.

Practice Questions Question: 54 Page: 279 Difficulty: 600

Each week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

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I think it is a small typo in statement (2): l.20 (small L) and not 1.20. Definitely looks like a 1. _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: A taxi company charges f cents for the first mile of the [#permalink]
01 Oct 2012, 08:22

1

This post received KUDOS

\(\)

carcass wrote:

X is the first mile and y are the additional miles

So, \(1*x + y * 9\) (9 because we have the additional miles less the first mile X \(10 - 1 = 9\) )

1)\(x + 9y = 0.90 + 8y\) ( we can't solve) INSUFF

2) \(x + 9y = 1.20 + 6y\) INSUFF

1) + 2) we can subsistute and solve

C should be the answer

The answer is correct, it is C. Just something to consider: when you are already given the variables - \(f\) and \(m\) the prices in cents for the first mile and the additional miles, respectively, no need to define new variables, just to have the prices in dollars. And I wouldn't suggest just picking automatically the \(x\) and \(y\) variables when dealing with some quantities with some specific meaning. \(f\) from first and \(m\) from miles are suggestive. With \(f\) and \(m\) your two equations would be: \(f+9m=90+8m\) \(f+9m=120+6m\) _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: A taxi company charges f cents for the first mile of the [#permalink]
01 Oct 2012, 04:22

Expert's post

1

This post was BOOKMARKED

SOLUTION

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

We need to find the value of \(f+9m\) (f cents for the first mile and m cents 9 miles).

(1) The company charges $0.90 for a 2-mile ride --> \(f+m=0.9\). Not sufficient. (2) The company charges $1.20 for a 4-mile ride --> \(f+3m=1.2\). Not sufficient.

(1)+(2) We have 2 distinct linear equations with 2 unknowns, hence we can solve for them and get the value of \(f+9m\). Sufficient.

Re: A taxi company charges f cents for the first mile of the [#permalink]
04 Oct 2012, 13:51

Expert's post

SOLUTION

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

We need to find the value of \(f+9m\) (f cents for the first mile and m cents 9 miles).

(1) The company charges $0.90 for a 2-mile ride --> \(f+m=0.9\). Not sufficient. (2) The company charges $1.20 for a 4-mile ride --> \(f+3m=1.2\). Not sufficient.

(1)+(2) We have 2 distinct linear equations with 2 unknowns, hence we can solve for them and get the value of \(f+9m\). Sufficient.

Answer: C.

Kudos points given to everyone with correct solution. Let me know if I missed someone. _________________

Re: A taxi company charges f cents for the first mile of the [#permalink]
04 Oct 2012, 14:04

Bunuel wrote:

SOLUTION

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

We need to find the value of \(f+9m\) (f cents for the first mile and m cents 9 miles).

(1) The company charges $0.90 for a 2-mile ride --> \(f+m=0.9\). Not sufficient. (2) The company charges $1.20 for a 4-mile ride --> \(f+3m=1.2\). Not sufficient.

(1)+(2) We have 2 distinct linear equations with 2 unknowns, hence we can solve for them and get the value of \(f+9m\). Sufficient.

Answer: C.

Kudos points given to everyone with correct solution. Let me know if I missed someone.

\(f\) and \(m\) are prices in cents, so the equations should be \(f+m=90\) and \(f+3m=120\). _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: A taxi company charges f cents for the first mile of the [#permalink]
10 Jan 2014, 07:22

Bunuel wrote:

A taxi company charges f cents for the first mile of the taxi ride and m cents for each additional mile. How much does the company charge for a 10-mile taxi ride?

(1) The company charges $0.90 for a 2-mile ride. (2) The company charges $1.20 for a 4-mile ride.

Practice Questions Question: 54 Page: 279 Difficulty: 600

We are given: f + 9*m = Total Cost, by the stem.

1) Tells us that f + m = 0.9, given that we have three unknowns but two equations, this is not enough. 2) This gives us f + 3m = 1.2, (which btw clearly is NOT the same info as in 1), so we have 3 unknowns and 2 equations, insufficient.

1 + 2. 3 equations and 3 unknowns, sufficient. We can add 1 and 2 together to solve for total cost, and we can add the info from the stem with one of the statements in 1 or 2 to solve for the third. C is our answer.

Re: A taxi company charges f cents for the first mile of the [#permalink]
05 May 2015, 13:22

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