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A taxi leaves Point A 5 hours after a bus left the same spot

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Intern
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Status: Life.. Be Kind to me
Joined: 12 Jan 2011
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Location: India
Schools: Tuck '14, HKUST, ISB
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A taxi leaves Point A 5 hours after a bus left the same spot [#permalink] New post 18 Apr 2011, 04:45
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Question Stats:

81% (03:03) correct 19% (01:58) wrong based on 79 sessions
A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.

(A) 44
(B) 46
(C) 48
(D) 50
(E) 52
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Mar 2013, 04:38, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Speed of bus [#permalink] New post 18 Apr 2011, 06:03
Let the speed of bus be v - 30, speed of taxi be v

The bus travelled a total of 8 hrs and taxi a total of 3 hrs.

Hence 8 * (v-30) = 3v
8v - 240 = 3v
5v = 240
v = 48 mph

PS : I referred GMATPill SC Guide this morning and got some wrong OA and some debatable OA. I think this probability extends even to the Quant section of the guide where some OA may be wrong. I will advise you to contact the author and inform the discrepancy.
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Status: Life.. Be Kind to me
Joined: 12 Jan 2011
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Location: India
Schools: Tuck '14, HKUST, ISB
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WE: Engineering (Telecommunications)
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Kudos [?]: 6 [0], given: 35

Re: Speed of bus [#permalink] New post 18 Apr 2011, 06:17
Thanks! even i got 48 as the answer
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Re: Speed of bus [#permalink] New post 18 Apr 2011, 06:31
I'm also getting 48 by both methods :

Speed of taxi = x

Speed of bus = x - 30

5(x-30) + 3 (x-30) = 3x

8x - 240 = 3x

5x = 240
x = 48

Relative Speed method :

5(x-30)/30 = 3

x = 18 + 30 = 48
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Re: Speed of bus [#permalink] New post 18 Apr 2011, 06:39
answer should be 48
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Re: Speed of bus [#permalink] New post 18 Apr 2011, 07:16
Let v be the speed of the taxi

3v = (v-30)8

=> v = 48 mph

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Re: Speed of bus [#permalink] New post 26 Mar 2013, 21:35
Expert's post
subhashghosh wrote:
I'm also getting 48 by both methods :

Speed of taxi = x

Speed of bus = x - 30

5(x-30) + 3 (x-30) = 3x

8x - 240 = 3x

5x = 240
x = 48

Relative Speed method :

5(x-30)/30 = 3

x = 18 + 30 = 48



Yes it's 48. The link to the original question is here:

A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 30 mph
slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.

(A) 44

(B) 46

(C) 48

(D) 50

(E) 52


The idea in this question is to set the distance for each of them to be equivalent. Each of them has a distinct "r*t". Set these equal to each other because the distance covered for each will be the same at the moment that the taxi overcomes the bus.
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Re: A taxi leaves Point A 5 hours after a bus left the same spot [#permalink] New post 31 Dec 2013, 08:56
meprarth wrote:
A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.

(A) 44
(B) 46
(C) 48
(D) 50
(E) 52


(T-B)(3) = 5B

and B= T-30

Hence, T =48

Answer is C

Gimme some Kudos will ya?

Cheers!
J :)
Re: A taxi leaves Point A 5 hours after a bus left the same spot   [#permalink] 31 Dec 2013, 08:56
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