I'm also getting 48 by both methods :
Speed of taxi = x
Speed of bus = x - 30
5(x-30) + 3 (x-30) = 3x
8x - 240 = 3x
5x = 240
x = 48
Relative Speed method :
5(x-30)/30 = 3
x = 18 + 30 = 48
Yes it's 48. The link to the original question is here:
A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 30 mph
slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.
The idea in this question is to set the distance for each of them to be equivalent. Each of them has a distinct "r*t". Set these equal to each other because the distance covered for each will be the same at the moment that the taxi overcomes the bus.
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