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A teacher assigns students to rooms in such a way that some

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A teacher assigns students to rooms in such a way that some [#permalink] New post 20 Jan 2006, 03:39
A teacher assigns students to rooms in such a way that some of the rooms can be empty and more than one student can be assigned to a room. In how many ways can the teacher assign 3 students to 2 different rooms?
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 [#permalink] New post 20 Jan 2006, 05:20
Is it 8?

2³=8, each student can be assigned to two rooms, without restrictions.
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 [#permalink] New post 20 Jan 2006, 14:58
Edit: First, i thought there 3 different romms instead of 2.
C (3:2)=3 (ways to choose 2 students out of 3)
AB/C, AC/B, BC/A
However, the order of rooms matter and there 2 ways to assign 2 students together and 1 student in 2 separate rooms
R#1 R#2
AB/ C
C/ AB

Total no. of ways=3*2=6
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 [#permalink] New post 20 Jan 2006, 16:49
Two possible cases

1. All 3 in a single room - 2 cases
2. 2 in one room and 1 in one room. - 3C2 * 2 = 6 cases

Total = 8
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 [#permalink] New post 20 Jan 2006, 19:23
allabout wrote:
Is it 8?

2³=8, each student can be assigned to two rooms, without restrictions.


I also got 8.

Hey allabout. How did you get this 2³ I mean 2 raise to 3.
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 [#permalink] New post 21 Jan 2006, 10:15
Can somebody tell me which possibility i am missing, if the answer is eight.

3,0
0,3
1,2
2,1
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 [#permalink] New post 21 Jan 2006, 10:34
Bhai wrote:
allabout wrote:
Is it 8?

2³=8, each student can be assigned to two rooms, without restrictions.


I also got 8.

Hey allabout. How did you get this 2³ I mean 2 raise to 3.


Bhai,

I think the explanation goes like this:
For each student there are 2 choices: Room 1 or Room 2

Hence Total choices = 2 * 2 * 2 = 8.
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 [#permalink] New post 21 Jan 2006, 10:39
prash_c wrote:
Can somebody tell me which possibility i am missing, if the answer is eight.

3,0
0,3
1,2
2,1


Here is I think all the possibilities are:

Students: A, B, C
Rooms: 1, 2

ABC, None
None, ABC
A, BC
B, AC
C, AB
AB, C
AC, B
BC, A
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 [#permalink] New post 21 Jan 2006, 23:00
its 2^3=8 choices..
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 [#permalink] New post 21 Jan 2006, 23:18
giddi77 wrote:
Bhai wrote:
allabout wrote:
Is it 8?

2³=8, each student can be assigned to two rooms, without restrictions.


I also got 8.

Hey allabout. How did you get this 2³ I mean 2 raise to 3.


Bhai,

I think the explanation goes like this:
For each student there are 2 choices: Room 1 or Room 2

Hence Total choices = 2 * 2 * 2 = 8.


I meant hos did he get 3 over 2. we write 2^3. See how allabout did 3 little above 2. I think you can do it only if you copy from somewhere it was already formatted.
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 [#permalink] New post 21 Jan 2006, 23:32
Bhai wrote:
giddi77 wrote:
Bhai wrote:
allabout wrote:
Is it 8?

2³=8, each student can be assigned to two rooms, without restrictions.


I also got 8.

Hey allabout. How did you get this 2³ I mean 2 raise to 3.


Bhai,

I think the explanation goes like this:
For each student there are 2 choices: Room 1 or Room 2

Hence Total choices = 2 * 2 * 2 = 8.


I meant hos did he get 3 over 2. we write 2^3. See how allabout did 3 little above 2. I think you can do it only if you copy from somewhere it was already formatted.


Hmm. That part I don't know :roll: I am not good at formatting stuff anyways...
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- Bernard Edmonds

  [#permalink] 21 Jan 2006, 23:32
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