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The video explanation for the above question is at 22:13
Part 1: Combination Framework - Dice, Marbles, Pocket Pair" Part 2: Apply to GMAT - Word Problems Part 3: Poker Probability - Pocket Pair vs Pocket Aces, Flush/Full House 00:00 - Intro 01:00 - Warmup 02:12 - Part 1 Overview: Combinations & Permutations vs Variations 08:35 - Part 1 Details: Picking Teams, Dice, Pocket Pair, Dating 17:21 - Part 2: Apply to GMAT - Word Problem #1 22:13 - Part 2: Apply to GMAT - Word Problem #2 31:34 - Part 2: Apply to GMAT - Word Problem #3 38:04 - Part 3: Poker Probability - Pocket Pair vs Pocket Aces 43:40 - Part 3: Poker Probability - Given Pocket Aces, 3-of-a-Kind? 46:13 - Part 3: Poker Probability - 1-Pair by 5th Flop 49:59 - Part 3: Poker Probability - Full House/Flush 1:00:00 - Conclusion
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
26 Dec 2012, 02:26
Expert's post
debayan222 wrote:
OA: D-700.
GMATPill/Bunuel, Is it really a 700+ level Q ? It's pretty easy guys...!
In that case combinations going to be an easy topic in GMAT..
GMAT combination/probability questions are fairly straightforward, so you won't see much harder questions on these topics on the exam. _________________
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
26 Dec 2012, 04:22
Expert's post
Bunuel wrote:
debayan222 wrote:
OA: D-700.
GMATPill/Bunuel, Is it really a 700+ level Q ? It's pretty easy guys...!
In that case combinations going to be an easy topic in GMAT..
GMAT combination/probability questions are fairly straightforward, so you won't see much harder questions on these topics on the exam.
Great to know that Bunuel...! Well, in that case Qs. in your signature and those in the GMAT Club tests (obviously apart from OG Qs.) would be suffice for 700+ in GMAT I think as far as combination/probability questions are concerned...!
Appreciate your thoughts on this... _________________
A team of 6 cooks is chosen from 8 Men and 5 Women [#permalink]
01 Sep 2013, 18:06
A team of 6 cooks is chosen from 8 Men and 5 Women. The team must have at least 2 men and at least 3 woen. How many ways can we form this team?
A) 140 B) 320 C) 560 D) 700 E) 840
Solution: We have two possibilities 2M 4F or 3M 3F (8C2)(5C3)+(8C3)(5C3)=700
I am trying another method but I am not getting it correctly. So for The first scenario 1) 3M 4F MMFFFF We can use a permutation approach. For the first man we have 8 choices. Second man 7. Likewise for the females. 5 for the first....2 for the last. We get (8*7)*(5*4*3*2) Now here is what is confusing me. Since I have MMFFFF and order doesn't matter the number of ways to arrange 3M's & 4F's is 6!/(2!*4!). I know I have to divide by 2! and 4! because we have duplicates and order doesn't matter but what about the 6!??? Should we include or exclude it? The answer has it excluded, but why?? I feel without the 6! we don't take into account MFFFMF or FFMFMF.... etc. What am I doing wrong?
Re: A team of 6 cooks is chosen from 8 Men and 5 Women [#permalink]
28 Sep 2013, 01:54
alphabeta1234 wrote:
A team of 6 cooks is chosen from 8 Men and 5 Women. The team must have at least 2 men and at least 3 woen. How many ways can we form this team?
A) 140 B) 320 C) 560 D) 700 E) 840
Solution: We have two possibilities 2M 4F or 3M 3F (8C2)(5C3)+(8C3)(5C3)=700
I am trying another method but I am not getting it correctly. So for The first scenario 1) 3M 4F MMFFFF We can use a permutation approach. For the first man we have 8 choices. Second man 7. Likewise for the females. 5 for the first....2 for the last. We get (8*7)*(5*4*3*2) Now here is what is confusing me. Since I have MMFFFF and order doesn't matter the number of ways to arrange 3M's & 4F's is 6!/(2!*4!). I know I have to divide by 2! and 4! because we have duplicates and order doesn't matter but what about the 6!??? Should we include or exclude it? The answer has it excluded, but why?? I feel without the 6! we don't take into account MFFFMF or FFMFMF.... etc. What am I doing wrong?
Hi,
You are only finding the different combinations and not concerned about the ordering of the combinations. Suppose the females are f1, f2, f3 , f4 and f5, including f1 and f2 means you do not have to consider f1, f2 and f2, f1 as separate. You do it only once. Hence you have to use the combination formula. _________________
A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
01 Oct 2013, 11:52
Hi,
I have the GMAT coming up on November 7th. I'm starting to panic because I get almost every PS problem that involves probabilities & selection wrong.
By selection I mean problems like this:
A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140 B) 320 C) 560 D) 700 E) 840
It's not that I don't get the formulas, I do. I just have no idea when to apply which formula. Or how you guys/ladies are looking at a problem and thinking "oh if I break this problem down into simpler terms, I can use formula ABC to solve it". It's exceedingly frustrating, because I'm getting about 90% of the problems incorrect. I just don't know what to do. I'm usually pretty good at math, I took the GRE about 7 years ago and was around 760 on the math section, but the GMAT questions just seem so different.
Last edited by Narenn on 01 Oct 2013, 20:24, edited 2 times in total.
Topic Moved. Always post the topic in relevant forum
Re: No idea how to apply the PS formulae I'm learning here [#permalink]
01 Oct 2013, 12:37
Expert's post
AccipiterQ wrote:
Hi,
I have the GMAT coming up on November 7th. I'm starting to panic because I get almost every PS problem that involves probabilities & selection wrong.
By selection I mean problems like this:
A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140 B) 320 C) 560 D) 700 E) 840
It's not that I don't get the formulas, I do. I just have no idea when to apply which formula. Or how you guys/ladies are looking at a problem and thinking "oh if I break this problem down into simpler terms, I can use formula ABC to solve it". It's exceedingly frustrating, because I'm getting about 90% of the problems incorrect. I just don't know what to do. I'm usually pretty good at math, I took the GRE about 7 years ago and was around 760 on the math section, but the GMAT questions just seem so different.
Question is not so difficult. Only thing matters is how do we simplify the information.
We know the team must have AT-LEAST 2 men and AT-LEAST 3 women. So the possible combinations are 2(M) and 4(W) or 3(M) and 3(W)
Case I :- 2 Men and 4 Women -------> selection of 2 men from 8 men AND selection of 4 women from 5 women ------> 8 C 2 * 5 C 4 -------> 28*5 -----> 140 teams
Case II :- 3 Men and 3 Women -------> selection of 3 men from 8 men AND selection of 3 women from 5 women ------> 8 C 3 * 5 C 3 -------> 56*10 -----> 560 teams
Total Number of teams = 140 + 560 = 700 ---------> Choice D
Hope that Helps!
PS :- For reference check my Permutations and Combinations article listed in my signature. _________________
Re: No idea how to apply the PS formulae I'm learning here [#permalink]
01 Oct 2013, 12:39
Narenn wrote:
AccipiterQ wrote:
Hi,
I have the GMAT coming up on November 7th. I'm starting to panic because I get almost every PS problem that involves probabilities & selection wrong.
By selection I mean problems like this:
A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140 B) 320 C) 560 D) 700 E) 840
It's not that I don't get the formulas, I do. I just have no idea when to apply which formula. Or how you guys/ladies are looking at a problem and thinking "oh if I break this problem down into simpler terms, I can use formula ABC to solve it". It's exceedingly frustrating, because I'm getting about 90% of the problems incorrect. I just don't know what to do. I'm usually pretty good at math, I took the GRE about 7 years ago and was around 760 on the math section, but the GMAT questions just seem so different.
Question is not so difficult. Only thing matters is how do we simplify the information.
We know the team must have AT-LEAST 2 men and AT-LEAST 3 women. So the possible combinations are 2(M) and 4(W) or 3(M) and 3(W)
Case I :- 2 Men and 4 Women -------> selection of 2 men from 8 men AND selection of 4 women from 5 women ------> 8 C 2 * 5 C 4 -------> 28*5 -----> 140 teams
Case II :- 3 Men and 3 Women -------> selection of 3 men from 8 men AND selection of 3 women from 5 women ------> 8 C 3 * 5 C 3 -------> 56*10 -----> 560 teams
Total Number of teams = 140 + 560 = 700 ---------> Choice D
Hope that Helps!
Thanks for the reply; it's actually a question posted here elsewhere, I just was using it as a sample of the type of problem. The issue I have is that I have no idea how to apply these formulae or when to apply them.
Re: No idea how to apply the PS formulae I'm learning here [#permalink]
01 Oct 2013, 12:47
1
This post received KUDOS
Expert's post
AccipiterQ wrote:
Thanks for the reply; it's actually a question posted here elsewhere, I just was using it as a sample of the type of problem. The issue I have is that I have no idea how to apply these formulae or when to apply them.
Ok. Refer the Article 'Permutations and Combinations' listed in my Signature below. I am sure it will help you understand when to apply which formula.
Re: No idea how to apply the PS formulae I'm learning here [#permalink]
01 Oct 2013, 16:51
Narenn wrote:
AccipiterQ wrote:
Thanks for the reply; it's actually a question posted here elsewhere, I just was using it as a sample of the type of problem. The issue I have is that I have no idea how to apply these formulae or when to apply them.
Ok. Refer the Article 'Permutations and Combinations' listed in my Signature below. I am sure it will help you understand when to apply which formula.
Thanks
Narenn
I just downloaded several of your PDFs, looks like I have some more study material! Thanks!
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
02 Oct 2013, 02:38
Expert's post
AccipiterQ wrote:
Hi,
I have the GMAT coming up on November 7th. I'm starting to panic because I get almost every PS problem that involves probabilities & selection wrong.
By selection I mean problems like this:
A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140 B) 320 C) 560 D) 700 E) 840
It's not that I don't get the formulas, I do. I just have no idea when to apply which formula. Or how you guys/ladies are looking at a problem and thinking "oh if I break this problem down into simpler terms, I can use formula ABC to solve it". It's exceedingly frustrating, because I'm getting about 90% of the problems incorrect. I just don't know what to do. I'm usually pretty good at math, I took the GRE about 7 years ago and was around 760 on the math section, but the GMAT questions just seem so different.
Merging similar topics. Please refer to the solutions above. _________________
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
15 Jan 2016, 13:31
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
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